在汇编编码中,使用masm32。
如何将值放入变量中,而不是在.data段中进行定义,而是通过LOCAL去除? 好的:
.486
.model flat, stdcall
option casemap :none
include \masm32\include\windows.inc
include \masm32\macros\macros.asm
include \masm32\include\masm32.inc
include \masm32\include\gdi32.inc
include \masm32\include\user32.inc
include \masm32\include\kernel32.inc
includelib \masm32\lib\masm32.lib
includelib \masm32\lib\gdi32.lib
includelib \masm32\lib\user32.lib
includelib \masm32\lib\kernel32.lib
.data
.code
start:
call main
exit
main proc
LOCAL dewit:DWORD
mov dewit, 0
print dewit
ret
main endp
end start
我试过这样的事情:
Mov dewit, 0
它没有用。但是,这段代码:
Mov dewit, input("enter a number")
确实给它留了一个值。
任何人
** LOCAL decleration只能在程序中
答案 0 :(得分:2)
你可以用调试器找到它。以下是从调试器查看的代码的开头:
CPU Disasm
Address Command Comments
00401000 CALL 0040100C ; call main
00401005 PUSH 0 ; /ExitCode = 0
00401007 CALL <JMP.&kernel32.ExitProcess> ; \KERNEL32.ExitProcess
0040100C PUSH EBP ; main
0040100D MOV EBP,ESP
0040100F ADD ESP,-4
00401012 MOV DWORD PTR SS:[LOCAL.1],0 ; dewit = 0
00401019 PUSH DWORD PTR SS:[LOCAL.1] ; /Arg1 => 0
0040101C CALL 00401024 ; print
00401021 LEAVE
00401022 RETN
因此print
被调用(请记住,print
是一个宏,因此一旦编译就会展开)。记得你把0推到print
:
CPU Disasm
Address Command Comments
00401024 PUSH EBP ; print (guessed Arg1)
00401025 MOV EBP,ESP
00401027 ADD ESP,-0C
0040102A PUSH -0B ; /StdHandle = STD_OUTPUT_HANDLE
0040102C CALL <JMP.&kernel32.GetStdHandle> ; \KERNEL32.GetStdHandle
00401031 MOV DWORD PTR SS:[LOCAL.1],EAX
00401034 PUSH DWORD PTR SS:[Arg1] ; /Arg1 => [Arg1] *** push 0 ***
00401037 CALL 00401060 ; \so.00401060
见第0x00401034
行,0被推送作为电话的参数。
让我们看看代码:
CPU Disasm
Address Command Comments
00401060 MOV EAX,DWORD PTR SS:[Arg1] ; eax = 0
00401064 LEA EDX,[EAX+3]
00401067 PUSH EBP
00401068 PUSH EDI
00401069 MOV EBP,80808080
0040106E /MOV EDI,DWORD PTR DS:[EAX] ; trying to dereference [0]...
代码试图在地址0处读取(也就是NULL指针错误),这是一个很大的禁忌。
查看print
中的macros.asm
宏,似乎此宏没有进行任何格式化,您应该使用printf
。
您的代码已修复(您需要msvcrt.inc
和msvcrt.lib
用于printf
宏,这仍然在macros.asm
中定义:
.486
.model flat, stdcall
option casemap :none
include \masm32\include\windows.inc
include \masm32\include\msvcrt.inc
include \masm32\macros\macros.asm
include \masm32\include\masm32.inc
include \masm32\include\gdi32.inc
include \masm32\include\user32.inc
include \masm32\include\kernel32.inc
includelib \masm32\lib\msvcrt.lib
includelib \masm32\lib\masm32.lib
includelib \masm32\lib\gdi32.lib
includelib \masm32\lib\user32.lib
includelib \masm32\lib\kernel32.lib
includelib \masm32\lib\masm32.lib
.data
format_string db "value: %d", 0
.code
start:
call main
exit
main proc
LOCAL dewit:DWORD
mov dewit, 0
print "printing value: "
printf ("value: %d", dewit)
ret
main endp
end start
大致相同的代码没有任何包含:
; compile and link with:
; ml test.asm /link /subsystem:console /defaultlib:kernel32.lib /defaultlib:msvcrt.lib
.686
.model flat, stdcall
option casemap: none
ExitProcess PROTO STDCALL :DWORD
externdef _imp__printf:PTR c_msvcrt
crt_printf equ <_imp__printf>
.data
fmt db "value: %d", 0
.code
start:
call MyFunc
invoke ExitProcess, 0
ret
MyFunc proc
LOCAL foo:DWORD
mov foo, 42
push foo
push offset fmt
call crt_printf
ret
MyFunc endp
end start
我也完全赞同@Jester:
此外,在您可以手动完成之前,请考虑不使用辅助功能 也是,并了解汇编程序正在做什么
宏很棒,但除非你能理解他们做了什么并手工实现,否则你应该避免使用它们。他们从初学者那里隐藏太多东西&#39;眼睛。
答案 1 :(得分:0)
由于您使用MASM32如果您尝试打印出32位值,请尝试使用str$
这样做:
print str$(dewit)
这会将内存位置dewit
的32位值转换为字符串,并在控制台上打印该字符串。这也可以立即起作用:
print str$(100)
注册:
print str$(eax)
如果您希望打印无符号值,也可以使用$ustr
。
这些宏在 MASM32 SDK
附带的高级宏帮助中进行了描述