Laravel 5.2 getNameOrUsername方法不起作用

Question

我正在搜索数据，就像在用户名中一样。我通过使用像<p>Jordan1</p>这样的静态名称来使用它，但是当我想让它变得动态时，就像拥有我的实际用户一样。当我使用这种方法

时，名称反映在它不起作用的页面上

{{ $user->getNameOrUsername() }}

作为回报，我收到了这个错误：

  

Builder.php第2130行中的BadMethodCallException：

     

调用未定义的方法Illuminate \ Database \ Query \ Builder :: getNameOrUsername（）

userblock.blade.php

    <div class="media">
        <a class="pull-left" href="#">
            <img class="media-object" alt="{{ $user->getNameOrUsername() }}" src="">
        </a>
        <div class="media-body">
            <h4 class="media-heading">
            <a href="#">{{ $user->getNameOrUsername() }}</a>
            </h4>
                @if ($user->location)
                    <p>{{ $user->location }}</p>
                @endif
        </div>
    </div>

results.blade.php

@include('layouts.--header')

<div class="container">
    <h4>Your search for "{{ Request::input('query') }}"</h4>

    @if (!$users->count())
        <p> No results found, sorry.</p>
    @else
    <div class="row">
        <div class="col-lg-12">
            @foreach ($users as $user)
                @include('search.userblock')
            @endforeach
        </div>
    </div>
    @endif
</div>

@include('layouts.--footer')

SearchController.php

<?php

namespace SCM\Http\Controllers;

use Illuminate\Http\Request;

use DB;
use SCM\User;
use Illuminate\Http\Requests;

class SearchController extends Controller
{
    public function getResults(Request $request)
    {   
        $query = $request->input('query');

        if (!$query) {
            return redirect ()->route('welcome');

        }

        $users = User::where(DB::raw("CONCAT(first_name, ' ', last_name)"), '
            LIKE', "%{$query}%")
            ->orWhere('username', 'LIKE', "%{$query}%")
            ->get();

        return view('search.results')->with('users', $users);
    }
}

routes.php文件

<?php

/*
|--------------------------------------------------------------------------
| Routes File
|--------------------------------------------------------------------------
|
| Here is where you will register all of the routes in an application.
| It's a breeze. Simply tell Laravel the URIs it should respond to
| and give it the controller to call when that URI is requested.
|
*/


/*
|--------------------------------------------------------------------------
| Application Routes
|--------------------------------------------------------------------------
|
| This route group applies the "web" middleware group to every route
| it contains. The "web" middleware group is defined in your HTTP
| kernel and includes session state, CSRF protection, and more.
|
*/

Route::group(['middleware' => ['web']], function () {
    Route::get('/login', function () {
    return view('auth/login');
});
    Route::get('/register', function () {
    return view('auth/login');
});

});

Route::group(['middleware' => 'web'], function () {
    Route::auth();

    Route::get('/', [
    'as' => 'welcome', 'uses' => 'WelcomeController@index'
]);

    Route::get('/profile', function () {
    return view('layouts/-profile');
});

    Route::get('profile/{username}', function () {
    return view('layouts/-profile');
});

    Route::get('settings/{username}', function () {
    return view('layouts/-settings');
});

    Route::get('/settings', function () {
    return view('layouts/-settings');
});


    Route::get('/home', 'HomeController@index');
});

/**
* Search
*/
Route::get('/search', [
    'as' => 'search.results', 'uses' => 'SearchController@getResults'
]);

Answer 1

它正在getNameOrUsername()模型上寻找User方法。您需要定义此方法。

仅供参考，如果它在Model上找不到该方法，则会在Illuminate\Database\Eloquent\Builder对象上查找该方法。如果它在那里找不到它，它会在Illuminate\Database\Query\Builder对象上查找它。如果它没有在那里找到它，它会抛出异常。这就是为什么它是一个＆＃34; BadMethodCallException＆＃34;在Illuminate\Database\Query\Builder。

Answer 2

该方法不随Laravel一起提供。如果你想使用它，你需要创建它。我认为可以这样做：

用户模型

public function getNameOrUsername() {

    return $this->name ? $this->name : $this->username;

}

然后在您的刀片模板中使用它，如

Hi {{ $user->getNameOrUsername() }}