Matplotlib - 当绘制时间时，它会在秒后放置十进制零

Question

这是我目前的情节：

我导入的'time'字符串是这样的：08：12：46，所以我想在最后剪掉零，但我似乎无法找到问题。另外，有没有办法以指数格式显示Y轴上的浮点数，这是我从csv导入的那个？

我刚开始研究matplotlib和numpy的工作，所以如果你有一些建议那就太棒了。

提前谢谢！

import numpy as np
import datetime as dt
import matplotlib
import matplotlib.pyplot as plt
import matplotlib.animation as animation
from matplotlib import style

print(plt.style.available)

style.use('ggplot')

fig = plt.figure()
ax1 = fig.add_subplot(1,1,1)

def animate(i):
    graph_data = open('C:\\Users\\arzuffi pc test\\Desktop\\VMI WIP - Copia (2)\\Cycle info\\_Current Cycle.csv','r').read()
    #graph_data = open('C:\\Users\\arzuffi pc test\\Desktop\\Visual Machine Interface Alpha 1.4.3\\Cycle info\\_Current Cycle.csv','r').read()
    lines = graph_data.split('\n')
    xs = []
    ys = []
    skip = 0
    for line in lines:        
        if skip < 7:
            skip += 1
        else:                
            if len(line) > 1:
                time, cycle, pc, pd, co, hv, cr, ph, gd_volt, gd_amp, gd_power, eva_amp, eva_volt, p_rpm, p_amp, r1_rpm, r1_amp, r2_rpm, r2_amp, hmdso, gas, ahc, diff_l, diff_r = line.split(';')
                #x, y = line.split(';')
                print(time)
                print(pc)
                xs.append(dt.datetime.strptime(time,'%H:%M:%S'))#.date())
                ys.append(pc)

        #print(i)
    #xs = matplotlib.dates.date2num(xs)    
    print(xs)    
    if len (xs) > 100:
        xs = xs[-100:]
    if len (ys) > 100:
        ys = ys[-100:] 
    ax1.clear()
    ax1.plot(xs, ys)
    plt.gcf().autofmt_xdate()

ani = animation.FuncAnimation(fig, animate,interval = 1000)
plt.show()

这些是数据：

Answer 1

您可以按如下方式指定要使用的格式：

xs = matplotlib.dates.date2num(xs)    # You need to keep this line

hfmt = matplotlib.dates.DateFormatter('%H:%M:%S')
ax1.xaxis.set_major_formatter(hfmt)
ax1.plot(xs, ys)   # You have this already

这将为您提供如下输出：