Question

我有三个表[PublicationNotice]，[PublicationNoticeClient]和[PublicationNoticeInvoice]。

Table1与table2和table3具有一对一的关系。

我正在使用存储过程将数据插入表中。我的表单由table1，table2和table3的所有属性组成。

我的问题是，当我将数据提交到这三个表时，它会在table1中插入所有数据accept table2_id和table3_id。

提示：我正在使用ASP .Net和MSSQL

我的存储过程如下所示：

CREATE procedure [dbo].[AddUpdatePublicationNotice]
    @ID bigint = NULL,
    @Title varchar(max)= NULL,
    @NewspaperName varchar(50) =NULL,
    @Cities varchar(max)= NULL,
    @PublicationSize varchar(8) =NULL,
    @PublicationDate date =NULL,
    @PublicationType varchar(50)= NULL,
    @NewspaperPageNo smallint= NULL,
    @Colored bit= NULL,
    @CaseNature varchar(15)= NULL,
    @ImagePath varchar(max)= NULL,
    @ClientId bigint =NULL,
    @InvoiceId bigint= NULL,
    @CreatedById bigint = NULL,
    @EditedById bigint= NULL,
    @EditedDate datetime =NULL,
    --******************************************--
    @ClientName varchar(max)= NULL,
    @ClientType varchar(50)= NULL,
    @ClientContactPerson varchar(max)= NULL,
    @ClientAddress varchar(max)= NULL,
    @ClientCity varchar(50) =NULL,
    @ClientCountry varchar(50)= NULL,
    --******************************************--
    @InvoiceDate date= NULL,
    @InvoiceTotalAmount bigint= NULL,
    @InvoicePaymentRecievedDate date= NULL,
    @InvoiceChequeNo bigint= NULL,
    @InvoiceBankName varchar(50)= NULL
    --******************************************--
    AS
    Insert into PublicationNotice (
       [Title]
      ,[NewspaperName]
      ,[Cities]
      ,[PublicationSize]
      ,[PublicationDate]
      ,[PublicationType]
      ,[NewspaperPageNo]
      ,[Colored]
      ,[CaseNature]
      ,[ImagePath]
      ,[ClientId]
      ,[InvoiceId]
      ,CreatedById
      )Values(
       @Title
      ,@NewspaperName
      ,@Cities
      ,@PublicationSize
      ,@PublicationDate
      ,@PublicationType
      ,@NewspaperPageNo
      ,@Colored
      ,@CaseNature
      ,@ImagePath
      ,@ClientId
      ,@InvoiceId
      ,@CreatedById)

      insert into [dbo].[PublicationNoticeClient] ( 
       [Name]
      ,[Type]
      ,[ContactPerson]
      ,[Address]
      ,[City]
      ,[Country]
      ,[CreatedById]) 
      Values(@ClientName
      ,@ClientType
      ,@ClientContactPerson
      ,@ClientAddress
      ,@ClientCity
      ,@ClientCountry
      ,@CreatedById)

      Insert Into [dbo].[PublicationNoticeInvoice] (
       [Date]
      ,[TotalAmount]
      ,[PaymentRecievedDate]
      ,[ChequeNo]
      ,[BankName]
      ,[CreatedById])
      Values (
       @InvoiceDate
      ,@InvoiceTotalAmount
      ,@InvoicePaymentRecievedDate
      ,@InvoiceChequeNo
      ,@InvoiceBankName
      ,@CreatedById)
      GO

我知道我可以先插入table2和table3值，然后从table2和table3中选择最后插入的值（即table2_id和table3_id），然后将它们插入table1

还有其他快速插入数据的方法???

Answer 1

您可以使用integer或@@IDENTITY , SCOPE_IDENTITY, IDENT_CURRENT方法检索最后一个ID。 OUTPUT是唯一安全的。{/ p>

您需要先插入表变量然后再查询

Output

Answer 2

--You need to declare two variables to get identity values from table 2 and table 3 As
DECLARE @table2_identity AS INT
DECLARE @table3_identity AS INT

--After insert in Table 2 set table2_identity variable as follows
SET @table2_identity = SELECT SCOPE_IDENTITY()

--After insert in Table 3 set table3_identity variable as follows
SET @table3_identity = SELECT SCOPE_IDENTITY()

--Then assign those variable values in insert query of Table 1

使用存储过程将数据插入三个连接表

2 个答案: