这段代码有效(我知道这是使用开关的错误方法),但似乎我正以错误的方式接近这个问题。我的网页上有两个dropdownmenu框,无论如何都可以混合使用。
但它可能有20个值,因此代码会快速增长。我必须知道用户在两个框中选择了什么以及它们的混合,因为它将显示关于框和它们的混合的数据。
所以简而言之,我的问题是;这样做有什么最佳解决方案吗?我希望页面加载速度快,易于维护。
function solveit() {
//These are dropdownlist that will just send and index or value as text
var selectedIndex1 = document.getElementById("selectedIndex1").value;
var selectedIndex2 = document.getElementById("selectedIndex2").value;
switch (selectedIndex1 + "|" + selectedIndex2){
case "1|1":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "1|2":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "1|3":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "1|4":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "1|5":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "2|1":
document.getElementById("IndexANDIndex").innerHTML = "Info about the two values"
break;
case "2|2":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "2|3":
document.getElementById("IndexANDIndex").innerHTML = "Info about the two values"
break;
case "2|4":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "2|5":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "3|1":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "3|2":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "3|3":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "3|4":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "3|5":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
//And so on...
case "1|1":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "2|1":
document.getElementById("IndexANDIndex").innerHTML = "Info about the two values"
break;
case "3|1":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "4|1":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
case "5|1":
document.getElementById("IndexANDIndex").innerHTML = "Information about the combination of them"
break;
//And so on...
default:
document.getElementById("IndexANDIndex").innerHTML = "NOTHING CHOOSEN"}
}
答案 0 :(得分:0)
为什么不将信息存储在对象中的每个值上,如下所示:
//the key is the name of the dropdown value and the string stores your info
//Objects keys can be a number or string so now have flexibility too
var valInfo = {
'1': 'one',
'2': 'two',
'3': 'three',
'4': 'four'
};
function info () {
var one = document.getElementById("selectedIndex1").value;
var two = document.getElementById("selectedIndex2").value;
return valInfo[one] + ' ' + valInfo[two];
} //returns "one two"
现在您只需要维护对象而不需要切换语句。将来,这些信息最好存储在json文件或数据库中。
如果每个保管箱都有基于所选号码的唯一信息,请使用2个对象:
var dropDown1 = {
'1': 'one',
'2': 'two',
'3': 'three',
'4': 'four'
};
var dropDown2 = {
'1': 'One',
'2': 'Two',
'3': 'Three',
'4': 'Four'
};
将以类似方式访问它们。现在,如果订单和组合相关,也许您应该重新评估应用程序的设计。
答案 1 :(得分:0)
我们可以用更少的开销编写相同的代码:
function solveit() {
//These are dropdownlist that will just send and index or value as text
var selectedIndex1 = document.getElementById("selectedIndex1").value;
var selectedIndex2 = document.getElementById("selectedIndex2").value;
document.getElementById("IndexANDIndex").innerHTML = getInfo(selectedIndex1 + "|" + selectedIndex2);
}
function getInfo(sel) {
switch (sel){
case "1|1": return "Information about the combination of them";
case "1|2": return "Information about the combination of them";
case "1|3": return "Information about the combination of them";
case "1|4": return "Information about the combination of them";
case "1|5": return "Information about the combination of them";
case "2|1": return "Info about the two values";
case "2|2": return "Information about the combination of them";
case "2|3": return "Info about the two values";
case "2|4": return "Information about the combination of them";
case "2|5": return "Information about the combination of them";
case "3|1": return "Information about the combination of them";
case "3|2": return "Information about the combination of them";
case "3|3": return "Information about the combination of them";
case "3|4": return "Information about the combination of them";
case "3|5": return "Information about the combination of them";
//And so on...
}
return "NOTHING CHOOSEN";
}
答案 2 :(得分:0)
因此item1和item1将是1 + 1 = 2而item2和item1将是2 + 1 = 3.这样我就不必为1 | 1而烦恼...
也许不是最好的解决方案,但我现在对此很满意。