底图无法找到沿轴警告的像素距离

时间:2016-01-09 19:21:06

标签: python matplotlib matplotlib-basemap

以下代码段会产生警告。 csv有一系列经度和纬度。 csv包含大约800,000个示例,

import pandas as pd
import matplotlib.pyplot as plt
from mpl_toolkits.basemap import Basemap

fname = "train.csv"
data = pd.read_csv(fname,sep=",",quotechar='"')
minlon=data["X"].min()
maxlon=data["X"].max()
minlat = data["Y"].min()
maxlat = data["Y"].max()


m =Basemap(projection='merc',llcrnrlat=minlat,urcrnrlat=maxlat,llcrnrlon=-minlon,urcrnrlon=maxlon,resolution='c')
m.drawcoastlines()
m.drawmapboundary()
x,y = m(list(data["X"].astype(float)),list(data["Y"].astype(float)))
m.scatter(x,y,1,marker='o',color='red')
plt.show()

以下是地图的显示方式:enter image description here

生成的警告显示: UserWarning: Unable to find pixel distance along axis for interval padding of ticks; assuming no interval padding needed. warnings.warn("Unable to find pixel distance along axis "

1 个答案:

答案 0 :(得分:1)

根据定义,墨卡托投影在极点附近不起作用,是不是有一些纬度-90度或90度的值?