需要在下拉列表中实现ajax更改输入字段的值

时间:2016-01-08 11:38:13

标签: javascript php jquery ajax

我在表单中填充了一行输入。它的变化只有一排。由于ajax使用id来显示php文件输出。但我需要更改每一行的值......

早期回应将受到高度赞赏。

function getAttendanceSub(categoryName) {
    $.ajax({
        type: "GET",
        url: "getAttendanceSub.php",
        data: "CategoryName=" + categoryName,
        success: function(result) {
            $("#subCategory").html(result);
        }
    });
};

的HTML

 $sql_category1 = "SELECT id, unit FROM unitmaster WHERE deleted = 'no' ";
         // echo $sql_batch;
         $res_category1 = mysql_query($sql_category1);
                         while ($row_category1 = mysql_fetch_assoc($res_category1)){
                        $vall = $row_category1["id"];
                        $captionn = $row_category1["unit"];

                         ?>
                        <option value="<?php echo $captionn ?>"><?php echo $captionn ?></option>
    <?php } ?>                                                      
    </select>

    </TD>
    <TD width="10%">
                    <input type="text"  name="txtbox2[]" />
              </TD>
    <TD width="10%"> <INPUT  type="text" name="txtbox3[]"  /> </TD>
    <TD width="10%"> <INPUT  type="text" name="txtbox4[]"  /> </TD>
    <!--<TD stylestyle="width:20px;"="width:50px;"> <INPUT type="checkbox" name="chkbox[]"/></TD>-->
    </TR>
    <?php
    $i++;
    ?>

</TABLE>

<br/>
 <INPUT type="button" value="Add" class="button" onClick="addRow('dataTable')" />

    <!--<INPUT type="button" value="Delete" onClick="deleteRow('dataTable')" />-->


</div>
</div>

<br/>
</div><br/><br/>
 <tr>

        <td align="center"><input type="submit" value="submit" name="submit"/></td>
    </tr>
            </div>
    </div>

    </div>

Screenshot

0 个答案:

没有答案