我在表单中填充了一行输入。它的变化只有一排。由于ajax使用id来显示php文件输出。但我需要更改每一行的值......
早期回应将受到高度赞赏。
function getAttendanceSub(categoryName) {
$.ajax({
type: "GET",
url: "getAttendanceSub.php",
data: "CategoryName=" + categoryName,
success: function(result) {
$("#subCategory").html(result);
}
});
};
$sql_category1 = "SELECT id, unit FROM unitmaster WHERE deleted = 'no' ";
// echo $sql_batch;
$res_category1 = mysql_query($sql_category1);
while ($row_category1 = mysql_fetch_assoc($res_category1)){
$vall = $row_category1["id"];
$captionn = $row_category1["unit"];
?>
<option value="<?php echo $captionn ?>"><?php echo $captionn ?></option>
<?php } ?>
</select>
</TD>
<TD width="10%">
<input type="text" name="txtbox2[]" />
</TD>
<TD width="10%"> <INPUT type="text" name="txtbox3[]" /> </TD>
<TD width="10%"> <INPUT type="text" name="txtbox4[]" /> </TD>
<!--<TD stylestyle="width:20px;"="width:50px;"> <INPUT type="checkbox" name="chkbox[]"/></TD>-->
</TR>
<?php
$i++;
?>
</TABLE>
<br/>
<INPUT type="button" value="Add" class="button" onClick="addRow('dataTable')" />
<!--<INPUT type="button" value="Delete" onClick="deleteRow('dataTable')" />-->
</div>
</div>
<br/>
</div><br/><br/>
<tr>
<td align="center"><input type="submit" value="submit" name="submit"/></td>
</tr>
</div>
</div>
</div>