好的，我有一个表，其中包括列：name，c_id，date。
该表中的某些条目遵循某个条件，我可以使用WHERE有效地选择，因此这不是问题。
然后，除了名称和c_id列之外，我还希望将三个日期的组分组：日期 - 1，日期和日期+ 1。换句话说，我希望输出的每一行代表所有具有相同名称的条目，c_id代表某个相关条目，并且发生在该条目的前一天和后一天之间，包括其自身。
我将如何做到这一点？
- 编辑：
（EDIT2：原始表应该是Table1的INNER JOIN，Table2是Table1.id = Table2.id）
示例数据：
Table1:
id | c_id | date | other stuff
-----------------------------------------------------
01 | abc | 2015/12/09 | whatever
02 | abc | 2015/12/09 | whatever
03 | abc | 2015/12/10 | relevant criterion
04 | abc | 2015/12/11 | whatever
05 | def | 2015/11/15 | whatever
06 | def | 2015/11/16 | relevant criterion
07 | abc | 2015/11/17 | whatever
08 | mnc | 2016/01/02 | whatever
09 | mnc | 2016/01/02 | whatever
10 | mnc | 2016/01/03 | whatever
11 | mnc | 2016/01/03 | whatever
12 | mnc | 2016/01/03 | whatever
13 | mnc | 2016/01/04 | relevant criterion
14 | mnc | 2016/01/05 | whatever
15 | mnc | 2016/01/05 | whatever
16 | mnc | 2016/01/06 | whatever
Table2:
id | Name | other stuff
--------------------------------------
01 | John | whatever
02 | John | whatever
03 | John | whatever
04 | John | whatever
05 | Mary | whatever
06 | Mary | whatever
07 | Mary | whatever
08 | Alice | whatever
09 | Alice | whatever
10 | Alice | whatever
11 | Alice | whatever
12 | Alice | whatever
13 | Alice | whatever
14 | Alice | whatever
15 | Alice | whatever
16 | Alice | whatever
示例所需的输出：
Name | c_id | pivot_date | count
------------------------------------------
John | abc | 2015/12/10 | 4
Mary | def | 2015/11/16 | 2
Alice | mnc | 2016/01/04 | 6
（pivot_date部分不一定特别是具有相关标准的部分，所涉及的任何一个日期都是好的。）
答案 0 :(得分：0)
更新了新的样本数据：
SELECT t.name, t.c_id, t.date pivot_date, COUNT(*) count
FROM record t
JOIN record t2
ON t2.name = t.name
AND t2.c_id = t.c_id
AND t2.date >= t.date - INTERVAL 1 DAY
AND t2.date <= t.date + INTERVAL 1 DAY
WHERE t.other_stuff = 'relevant criterion'
GROUP BY t.name, t.c_id, t.date
-
更新了新的样本数据：
SELECT t2.name, t1.c_id, t1.date pivot_date, COUNT(*) count
FROM table1 t1
JOIN table1 to1
ON to1.c_id = t1.c_id
AND to1.date >= t1.date - INTERVAL 1 DAY
AND to1.date <= t1.date + INTERVAL 1 DAY
JOIN table2
ON t2.id = t1.id
WHERE t1.other_stuff = 'relevant criterion'
GROUP BY t2.name, t1.c_id, t1.date
答案 1 :(得分：0)
这是一种方式：
@dt := '2015-12-10'
SELECT Name , c_id, MAX(`date`) maxdate, COUNT(*) countof
FROM table1
WHERE date >= @dt - INTERVAL 1 DAY AND `date` < @dt + INTERVAL 2 DAY
GROUP BY Name , c_id
请注意，日期列可以是MIN（日期）作为替代
答案 2 :(得分：0)
我必须使用分析LAG / LEAD函数在Oracle中构建它。我不知道你是否可以在MYSQL中模拟这些函数（看here进行模拟）
table1是您的数据
with
relevant as
(
select *
from (
select
nm,
c_id,
stuff,
dt,
lag(dt,1) over ( order by nm, dt, c_id) prev,
lead(dt,1) over ( order by nm, dt, c_id) nxt
from table1 )
where stuff = 'relevant criterion'
)
select
d.nm,
d.c_id,
to_char(d.dt,'DD-MON-YYY') dt,
d.stuff,
count(*) over (partition by d.nm, d.c_id) cnt
from table1 d
where ( d.dt in ( select rp.prev from relevant rp where d.nm = rp.nm and d.c_id = rp.c_id )
OR
d.dt in ( select rn.nxt from relevant rn where d.nm = rn.nm and d.c_id = rn.c_id )
OR
d.dt in ( select rn.dt from relevant rn where d.nm = rn.nm and d.c_id = rn.c_id )
)
;
结果：
NM C_ID DT STUFF CNT
Alice mnc 03-JAN-016 whatever 6
Alice mnc 03-JAN-016 whatever 6
Alice mnc 03-JAN-016 whatever 6
Alice mnc 05-JAN-016 whatever 6
Alice mnc 04-JAN-016 relevant criterion 6
Alice mnc 05-JAN-016 whatever 6
John abc 11-DEC-015 whatever 4
John abc 10-DEC-015 relevant criterion 4
John abc 09-DEC-015 whatever 4
John abc 09-DEC-015 whatever 4
Mary def 15-NOV-015 whatever 2
Mary def 16-NOV-015 relevant criterion 2
您可以通过将此查询创建为视图并添加where stuff = 'relevant criterion'过滤条件
NM C_ID DT STUFF CNT
Alice mnc 04-JAN-016 relevant criterion 6
John abc 10-DEC-015 relevant criterion 4
Mary def 16-NOV-015 relevant criterion 2
答案 3 :(得分：0)
这是一种天真的方式。它有点工作：
select t2.Name, t1.c_id, min(t1.Date) as pivot_date, count(*) as cnt
from Table1 t1 inner join Table2 t2 on t2.id = t1.id
where <criteria...>
group by t2.Name, t1.c_id, datediff(t1.Date, '2015-01-01') div 3
这种方法根据起点任意将日历划分为三天。
可以有连续的日期，形成第一个区块的结尾和下一个区块的开始。我怀疑你是否想要那个，我会看到我是否能找到能够提供更好平衡的东西。
您遗漏的过滤条件有多复杂？