我做了这个,但是错误[NSString stringWithFormat:@"%@",@" \ u0001 [xxxx]"]
NSDictionary *parameters = [NSDictionary dictionaryWithObjectsAndKeys:
[NSString stringWithFormat:@"%@", @"\u0001[xxxx]"], @"content",
[NSNumber numberWithBool:anonymous],@"aaaaa",
nil];
return [manager POST:submitCommentUrlString parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject){
...
} failure:^(AFHTTPRequestOperation *operation, NSError *error){
...
}];
答案 0 :(得分:2)
尝试使用
[[NSString stringWithFormat:@"%@", @"\u0001[xxxx]"] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
而不是
[NSString stringWithFormat:@"%@", @"\u0001[xxxx]"]
以便在字典中设置对象。
答案 1 :(得分:0)
[NSString stringWithFormat:@"%C", 0x1]
这是\ u0001