如果(isset($ _ POST [' btn-signup']))怎么办?

时间:2016-01-02 04:52:27

标签: php mysqli

if(isset($ _ POST [' btn-signup']))行有什么作用?我在学习php。我已经完成了一些关于基础知识的课程,现在通过示例程序学习。这是登录表单的php部分。它显然工作正常,但我仍然不太了解$ _POST的使用。

<?php
session_start();
if(isset($_SESSION['userSession'])!="")
{
 header("Location: home.php");
}
include_once 'dbconnect.php';

if(isset($_POST['btn-signup']))
{
 $uname = $MySQLi_CON->real_escape_string(trim($_POST['user_name']));
 $email = $MySQLi_CON->real_escape_string(trim($_POST['user_email']));
 $upass = $MySQLi_CON->real_escape_string(trim($_POST['password']));

 $new_password = password_hash($upass, PASSWORD_DEFAULT);

 $check_email = $MySQLi_CON->query("SELECT email FROM users WHERE email='$email'");
 $count=$check_email->num_rows;

 if($count==0){


  $query = "INSERT INTO users(username,email,password) VALUES('$uname','$email','$new_password')";


  if($MySQLi_CON->query($query))
  {
   $msg = "<div class='alert alert-success'>
      <span class='glyphicon glyphicon-info-sign'></span> &nbsp; successfully registered !
     </div>";
  }
  else
  {
   $msg = "<div class='alert alert-danger'>
      <span class='glyphicon glyphicon-info-sign'></span> &nbsp; error while registering !
     </div>";
  }
 }
 else{


  $msg = "<div class='alert alert-danger'>
     <span class='glyphicon glyphicon-info-sign'></span> &nbsp; sorry email already taken !
    </div>";

 }

 $MySQLi_CON->close();

1 个答案:

答案 0 :(得分:0)

if(isset($_POST['btn-signup']))

当表单通过http'post'方法提交到php url时 ,该表单中的命名值将添加到$ _POST,其各自的名称为键。此行检查php文档是否收到名为'btn-signup'的值

源表单可能包含类似

的内容
<input type="text" name="btn-signup" />