Question

我有两个文件是在执行几个脚本并运行少量查询后得到的，这两个文件的差异（每个文件有两列，名称和编号）现在存储在第三个文件中第三个文件包含三列！

!  <Employee Name1> <Employee Number1>
!  <Employee Name1> <Employee Number2>
!  <Employee Name3> <Employee Number4>
!  <Employee Name3> <Employee Number5>

如何一次读取2行文件并报告类似

的内容

<Employee Name1> has different Employee ID.It is <Employee Number1> in File1 and <Employee Number2> in File2

Answer 1

使用bash，你可以在while循环中读取2行：

while read -r _ name num1; read -r _ name num2; do
    echo "$name has different Employee ID.It is $num1 in File1 and $num2 in File2"
done < file3

Answer 2

正如@shellter建议的那样，几乎可以肯定有更好的方法来实现你所描述的目标，但本着“你要求的小心”这一点，这里有一个awk程序这就是你所要求的（通过一点点理智检查： - ）：

awk -F'[<>]' '
  function reset() { employee=e1="" }
  NR % 2 { employee=$2; e1 = $4; next; }
  { if ($2 == employee) {
      print employee " is " e1 " in File1 and " $4 " in File2";
    } else {
      print "INTERNAL ERROR at line " NR ": " employee " vs " e1 "; resetting ..."; 
    }
    reset();
  }'

Answer 3

假设名称和ID不包含空格（根据问题评论中的示例）：

awk '
    $2 == name && $3 != id {
        print name, id, $3
    }
    {
        name = $2
        id = $3
    }
'

Answer 4

AWK

awk 'NR==FNR{arr[$1]=$2;next}{if(($1 in arr) && !(arr[$1]==$2)){print $1, "has a different Employee ID.It is",arr[$1],"in file 1 and ",$2,"in file 2" }}' file1 file2

其中file1和file2是文件的路径

例如

文件1

John 1357
Joe 2362

file2的

John 1357
Joe 2361
Joey 25135
Julius 1235

输出

Joe has a different Employee ID.It is 2362 in file 1 and  2361 in file 2

Linux阅读文件逐行和报告

4 个答案: