Question

我在选择一行时尝试推送新视图。

let identifiers:[String] = ["vc1", "vc2", "vc3", "vc4", "vc5"]

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    let identifier = identifiers[indexPath.row]
    let storyboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
    let vc: UINavigationController = storyboard.instantiateViewControllerWithIdentifier("\(identifier)") as! UINavigationController
    self.presentViewController(vc, animated: true, completion: nil)

}

使用此tableView调用的所有不同视图都有自己的类和Storyboard ID。

目前我收到错误：

无法转换类型＆＃39; testApp.CalculatorViewController＆＃39;的值到＆＃39; UINavigationController＆＃39;

Answer 1

我认为您正在尝试将UIViewController转换为UINavigationController。

请试试这个。这可能会对你有帮助。

let identifiers:[String] = ["vc1", "vc2", "vc3", "vc4", "vc5"]

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
let identifier = identifiers[indexPath.row]
let storyboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
let vc: UIViewController = storyboard.instantiateViewControllerWithIdentifier("\(identifier)") as! UIViewController
self.navigationController?.pushViewController(vc, animated: true, completion: nil)

}

为UITableView的每一行推送不同的UIView

1 个答案: