Question

我们将PHP从5.3升级到5.6，现在我收到了错误和警告。我对从php 5.3中弃用的内容有点困惑，这会引起这种情况。

get_class

if( get_class($favorite) === false ) $favorite = new favorite;警告

$commQuery

class getCommDetails{ var $community; var $commURL; var $commAddress; var $commPhone; var $cid; var $commMin; var $commMax; function getCommDetails($community){ $ret = false; if( get_class($db) === false ) $db = new DB(DB_SERVER, DB_USER, DB_PASS, DB_NAME); $this->community = $community; $commQuery = $db->getEntry('communities', '*', "communities.community = '$this->community'"); if( $db->numrows($commQuery) === 1) { $commResults = $db->fetch_array($commQuery); $this->commURL = $commResults['url']; $this->commAddress = $commResults['address']; $this->commPhone = $commResults['sales_phone']; $this->cid = $commResults['cid']; $this->vars = $commResults; //$this->commURL = $fpResults $ret = true; } return $ret; } };是致命错误第43行

    <?php
 class DB {
// Class Variables
var $connection;
var $queryStr;

// Class Constructor
function DB($DB_Server, $DB_User, $DB_Pass, $DB_Name){
    $this->connection = mysqli_connect("$DB_Server", "$DB_User", "$DB_Pass","$DB_Name") or die("MySQL Connection Err: ". mysqli_error($this->connection));
    //mysql_select_db("$DB_Name") or die("MySQL DB Err: ".mysql_error());
}

// Class Functions
function addEntry($table, $fieldlist, $valuelist){
    $this->queryStr = "INSERT INTO `". $table ."` ($fieldlist) VALUES ($valuelist)";
    return $this->query($this->queryStr);
}

function updateEntry($table, $fieldvalues, $where = NULL){
    if( is_array($fieldvalues) ){
        $c=0;$numFields=count($fieldvalues);
        foreach($fieldvalues as $fieldname => $value){
            if($fieldname == 'inventoryAction'){
                $c++;
                continue;
            }
            $fieldvaluelist .= $fieldname."='".$value."'";
            if($numFields > 1){
                if($c < $numFields-1)
                    $fieldvaluelist .= ",";
            }
            $c++;
        }
    } else {
        return false;
    }
    $this->queryStr = "UPDATE `". $table ."` SET ".$fieldvaluelist;
    if($where !== NULL)
        $this->queryStr .= " WHERE $where";
    return $this->query($this->queryStr);
}

function removeEntry($table, $where = NULL){
    if($where != NULL){
        $this->queryStr = "DELETE FROM `". $table ."` WHERE $where";
        return $this->query($this->queryStr);
    } else {
        return false;
    }
}

  function getEntry($table, $fieldlist, $where=NULL, $whereon=NULL, $groupby = NULL){
    $this->queryStr = "SELECT $fieldlist FROM ".$table;
    if($whereon !== NULL)
        $this->queryStr .= " ON $whereon";
    if($where !== NULL)
        $this->queryStr .= " WHERE $where";
    if($groupby !== NULL)
        $this->queryStr .= " GROUP BY $groupby";

    return $this->query($this->queryStr);
}

function fetch_array($qResults, $recordType = NULL){
    if($recordType == "MYSQL_NUM"){
        return mysqli_fetch_array($qResults, MYSQL_NUM);
    } elseif($recordType == "MYSQL_ASSOC"){
        return mysqli_fetch_array($qResults, MYSQL_ASSOC);
    } else {
        return mysqli_fetch_array($qResults);
    }
}

function fetch_object($qResults){
    return mysqli_fetch_object($qResults);
}

function numrows($qResults){
    if(!$qResults)
        return false;
    else
        return mysqli_num_rows($qResults);
}

function getLastID(){
    return mysqli_insert_id($this->connection);
}

function getQuery(){
    return $this->queryStr;
}

function query($query){
    if(!$query)
        return false;
    else
        return mysqli_query($this->connection,$query);
}
 };
 ?>

数据库连接代码

react-router

Answer 1

删除条件

if( get_class($db) === false )

尝试不用if：

写

        $db = new DB(DB_SERVER, DB_USER, DB_PASS, DB_NAME);

PHP致命错误：调用成员函数getEntry（）将php 5.3升级到5.6

1 个答案: