Question

我是新手程序员，我想知道为什么我的代码无法从我的Mysql DB中获取正确的数据。

mysql_connect('localhost',"root","password");
mysql_select_db("Torch");
$playerbal = mysql_query("SELECT money FROM table WHERE name = '$player'");

如果我使用此代码，那么我将$ playerbal视为资源ID＃7

我找到了一些针对此Resouce id＃7错误的解决方案。如果我使用 mysql_fetch_array ，我只会＆＃34;数组＆＃34;

Answer 1

mysql_ *函数现已弃用，不应再使用了。您的代码无法正常工作，因为您需要使用mysqli_fetch_array（）才能使用数据库连接处理程序检索表中的实际数据尝试使用这样的东西：

//Create DB connection 
$con=mysqli_connect("localhost","root","password","Torch");

// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

// Perform queries 
$result = mysqli_query($con, "SELECT money FROM table WHERE name = '$player'") or die(mysqli_error($con)); 

//Retrieve the info(row) from the retrieved recordset and loop through it
while($row = mysqli_fetch_array( $result )) {

  //Retrieve the needed field from the row
  $data=$row['money'];

  //do your stuff here

}

//Close connection
mysqli_close($con);

BTW别忘了清理你的输入。

Answer 2

mysql_query（）语句返回指向结果集的资源指针，而不是数据本身。您需要使用mysql_fetch_array（）来检索表中的实际数据。

这里是sol

$row = mysql_fetch_array($playerbal);
$data = $row['money'];
echo $data;

Answer 3

如果您想获得所有行的资金列，请使用此代码 -

mysql_connect('localhost',"root","password");
mysql_select_db("Torch");
$playerbal = mysql_query("SELECT money FROM table WHERE name = '{$player}'");
while($data = mysql_fetch_array($playerbal)){
      echo $data[0];  //there is only one column so this column is stored into 0 index.

}

PHP Mysql查询数据不正确

3 个答案: