有没有人知道为什么libuv会在使用仿函数结构而不是实际函数作为回调时发生段错误。在下面的示例中,我创建了使用的结构CB而不是connection_cb。在操作符()中发生段错误。
#include <uv.h>
#include <stdio.h>
#include <stdlib.h>
uv_buf_t alloc_buffer(uv_handle_t * handle, size_t size);
void connection_cb(uv_stream_t * server, int status);
void read_cb(uv_stream_t * stream, ssize_t nread, uv_buf_t buf);
struct CB {
State *state_;
CB(State *state) : state_(state) {}
void operator()(uv_stream_t *server, int status) {
uv_tcp_t * client = (uv_tcp_t *)malloc(sizeof(uv_tcp_t));
/* if status not zero there was an error */
if (status == -1) {
printf("error 2\n");
}
/* initialize the new client */
uv_tcp_init(loop, client);
/* now let bind the client to the server to be used for incomings */
if (uv_accept(server, (uv_stream_t *) client) == 0) {
/* start reading from stream */
int r = uv_read_start((uv_stream_t *) client, (uv_alloc_cb)alloc_buffer, read_cb);
if (r) {
printf("error 3\n");
}
state_->onConnect();
} else {
/* close client stream on error */
uv_close((uv_handle_t *) client, NULL);
}
}
};
CB cb;
uv_tcp_t server;
uv_loop_t * loop;
int main() {
loop = uv_default_loop();
/* convert a humanreadable ip address to a c struct */
struct sockaddr_in addr;
uv_ip4_addr("127.0.0.1", 3005, &addr);
/* initialize the server */
uv_tcp_init(loop, &server);
/* bind the server to the address above */
uv_tcp_bind(&server, (const struct sockaddr *)&addr, 0);
/* let the server listen on the address for new connections */
int r = uv_listen((uv_stream_t *) &server, 128, (uv_connection_cb)&cb);
if (r) {
printf("error 1\n");
return -1;
}
/* execute all tasks in queue */
return uv_run(loop, UV_RUN_DEFAULT);
}
/**
* Callback which is executed on each new connection.
*/
void connection_cb(uv_stream_t * server, int status) {
/* dynamically allocate a new client stream object on conn */
uv_tcp_t * client = (uv_tcp_t *)malloc(sizeof(uv_tcp_t));
/* if status not zero there was an error */
if (status == -1) {
printf("error 2\n");
}
/* initialize the new client */
uv_tcp_init(loop, client);
/* now let bind the client to the server to be used for incomings */
if (uv_accept(server, (uv_stream_t *) client) == 0) {
/* start reading from stream */
//int r = uv_read_start((uv_stream_t *) client, (uv_alloc_cb)alloc_buffer, read_cb);
int r = 0;
if (r) {
printf("error 3\n");
}
} else {
/* close client stream on error */
uv_close((uv_handle_t *) client, NULL);
}
}
/**
* Callback which is executed on each readable state.
*/
void read_cb(uv_stream_t * stream, ssize_t nread, uv_buf_t buf) {
/* dynamically allocate memory for a new write task */
uv_write_t * req = (uv_write_t *) malloc(sizeof(uv_write_t));
/* if read bytes counter -1 there is an error or EOF */
if (nread == -1) {
printf("error 4\n");
uv_close((uv_handle_t *) stream, NULL);
}
/* write sync the incoming buffer to the socket */
int r = uv_write(req, stream, &buf, 1, NULL);
if (r) {
printf("error 5\n");
}
}
/**
* Allocates a buffer which we can use for reading.
*/
uv_buf_t alloc_buffer(uv_handle_t * handle, size_t size) {
return uv_buf_init((char *) malloc(size), size);
}
答案 0 :(得分:2)
粘贴的代码无效,因为libuv需要key
中的函数指针 - 您提供的是指向结构的指针。这种结构碰巧有uv_listen
,但这并不会使结构的地址成为处理器可以跳转到并执行代码的地址。 operator()
就像您的结构的任何其他方法一样,但您可以使用简单operator()
或()
来调用,以使代码更具可读性。另外,由于.operator()
是非静态的,因此它期望隐含引用operator()
,而libuv将不会提供这种引用,因为它不需要。
要实现您要执行的操作,您应该提供正常的C函数回调并将额外的上下文数据存储在句柄的this
字段中:
而不是:
.data
使用:
int r = uv_listen((uv_stream_t *) &server, 128, (uv_connection_cb)&cb);
uv句柄上的 server.data = &cb;
int r = uv_listen((uv_stream_t *) &server, 128, [](uv_stream_t *server, int status){
(*(CB*)server->data)(server, status);
});
字段完全是为了这个目的而提供的。