Question

假设我有一个名为mymat的矩阵。我需要排除列key和AMLM12014N-R，并创建另一个名为newmat的矩阵。我可以这样做：newmat <- mymat[,-c(1,4)]，但有没有办法通过调用列名本身来做到这一点？这样的事情：newmat <- mymat[,-c("key","AMLM12014N-R")]？

mymat <- structure(c("chr5:12111", "chr5:12111", "chr5:12113", "chr5:12114", 
"chr5:12118", "0N", "0N", "1N", "0N", "0N", "00", "00", "00", 
"11", "10", "00", "00", "1N", "0N", "00"), .Dim = c(5L, 4L), .Dimnames = list(
    c("34", "35", "36", "37", "38"), c("key", "AMLM12001KP", 
    "AMAS-11.3-Diagnostic", "AMLM12014N-R")))

Answer 1

我们可以使用setdiff

mymat[,setdiff(colnames(mymat), c("key","AMLM12014N-R"))]

或%in%

mymat[,!colnames(mymat) %in% c("key","AMLM12014N-R")]

排除R调用列名称中的列

1 个答案: