Question

#include<stdio.h>

/*Counts digits, white numbers, others*/

main()
{
    int c, i, nwhite, nother;
    int ndigit[10];
    nwhite=nother=0;
    for(i=0; i<10; ++i)
        ndigit[i]=0;
    while((c=getchar())!=EOF)
        if(c>='0' && c<=9)
            ++ndigit[c-'0'];
        else if(c=='void' || c=='\n' || c=='\t')
            ++nwhite;
        else
            ++nother;
    printf("digits= ");
    printf("%d", ndigit[i]);
    printf("whitespace=%d, other=%d\n", nwhite, nother);
}

Answer 1

三个变化：

if(c>='0' && c<=9)至if(c>='0' && c<='9')
将c=='void'更改为c==' '

打印每个数字的计数也应该在循环内。

for(i=0; i<10; ++i)
    printf("%d ", ndigit[i]);

最终代码：

#include<stdio.h>

/*Counts digits, white numbers, others*/

main()
{
    int c, i, nwhite, nother;
    int ndigit[10];
    nwhite=nother=0;
    for(i=0; i<10; ++i)
        ndigit[i]=0;
    while((c=getchar())!=EOF)
        if(c>='0' && c<='9')
            ++ndigit[c-'0'];
        else if(c==' ' || c=='\n' || c=='\t')
            ++nwhite;
        else
            ++nother;
    printf("digits= ");
    for(i=0; i<10; ++i)
        printf("%d ", ndigit[i]);
    printf("\nwhitespace=%d, other=%d\n", nwhite, nother);
}

示例输出：

[tthangavel@wtl-lview-7 test]$ ./a.out
43n lkj1234;la sdf;akspjfoiwqe
asdf;lkq324m n;afds
digits= 0 1 2 3 3 0 0 0 0 0
whitespace=6, other=37
[tthangavel@wtl-lview-7 test]$

计算数字，空格和其他字符

1 个答案: