node-archiver：归档多个目录

Question

当您知道路径时，是否可以归档多个目录？让我们说： <hosts> <host instances="" name="*" roles="alpha"> <tags/> </host> <host instances="" name="server1" id="alpha,beta"> <tags> <tag app-id="1" instance="1" name="alpha"/> <tag app-id="2" instance="2" name="beta"/> </tags> </host> <host instances="" name="server2" id="beta,gama"> <tags> <tag app-id="1" instance="1" name="beta"/> <tag app-id="2" instance="2" name="gama"/> </tags> </host> </hosts> def main1(file=outfile): tree = et.parse(file) root = tree.getroot() thingy = root.find('hosts') for thing in thingy: if "server1" in thing.get('name'): root.remove(thing) #thingy.remove(thing) print thingy 。我现在正在做的是将目录复制到一个目录中，让我们说：['/dir1','dir2', .., 'dirX']并执行以下操作：

/dirToZip

是否有方法将目录附加到存档中而不是批量需要的特定模式？提前谢谢！

Answer 1

您可以使用bulk(mappings)。尝试：

var output = fs.createWriteStream(__dirname + '/bulk-output.zip');
var archive = archiver('zip');

output.on('close', function() {
    console.log(archive.pointer() + ' total bytes');
    console.log('archiver has been finalized and the output file descriptor has closed.');
});

archive.on('error', function(err) {
    throw err;
});

archive.pipe(output);

archive.bulk([
    { expand: true, cwd: 'views/', src: ['*'] },
    { expand: true, cwd: 'uploads/', src: ['*'] }
]);

archive.finalize();

<强>已更新

或者你可以更轻松地做到这一点：

var output = fs.createWriteStream(__dirname + '/bulk-output.zip');
var archive = archiver('zip');

output.on('close', function() {
    console.log(archive.pointer() + ' total bytes');
    console.log('archiver has been finalized and the output file descriptor has closed.');
});

archive.on('error', function(err) {
    throw err;
});

archive.pipe(output);

archive.directory('views', true, { date: new Date() });
archive.directory('uploads', true, { date: new Date() });

archive.finalize();

Answer 2

对于遇到同样问题的每个人来说，最终对我有用的是： 假设你有以下结构：

/用户/ X /桌面/ TMP

| __ dir1

| __ dir2

| __ dir3

var baseDir = '/Users/x/Desktop/tmp/';
var dirNames = ['dir1','dir2','dir3']; //directories to zip

var archive = archiver.create('zip', {});
archive.on('error', function(err){
    throw err;
});

var output = fs.createWriteStream('/testDir/myZip.zip'); //path to create .zip file
output.on('close', function() {
    console.log(archive.pointer() + ' total bytes');
    console.log('archiver has been finalized and the output file descriptor has closed.');
});
archive.pipe(output);

dirNames.forEach(function(dirName) {
    // 1st argument is the path to directory 
    // 2nd argument is how to be structured in the archive (thats what i was missing!)
    archive.directory(baseDir + dirName, dirName);
});
archive.finalize();

Answer 3

@ sstauross的答案对我来说非常合适。我添加了一些代码，允许在zip进程中添加目录和文件的混合：

假设文件夹/Users/x/baseFolder具有以下结构：

 /Users/x/baseFolder
 | __ dir1
   | __ file1.txt 
   | __ file2.txt
 | __ dir2
   | __ file3.txt
   | __ file4.txt
 | __ dir3
   | __ file5.txt
   | __ file6.txt
   | __ file7.txt
 | __ file8.txt
 | __ file9.txt
 | __ file10.txt

我可以执行以下操作来创建具有以下结构和内容的/Users/x/baseFolder/result.zip文件夹：

/Users/x/baseFolder/result.zip 
 | __ dir1
   | __ file1.txt 
 | __ dir2
   | __ file3.txt
   | __ file4.txt
 | __ dir3
   | __ file6.txt
   | __ file7.txt
 | __ file8.txt
 | __ file9.txt


function zipFolder(baseFolder) {
  var archive = archiver('zip');

  var fileNames = [
    'dir1/file1.txt',
    'dir3/file6.txt',
    'dir3/file7.txt',
    'file8.txt',
    'file9.txt'
  ];
  var folderNames = [
    'dir2',
  ]

  var output = fs.createWriteStream(path.join(baseFolder, "result.zip"));

  output.on('close', function () {
    console.log(archive.pointer() + ' total bytes');
    console.log('archiver has been finalized and the output file descriptor has closed.');
  });

  archive.on('error', function (err) {
    throw err;
  });

  archive.pipe(output);

  for (i = 0; i < fileNames.length; i++) {
    var stream = fs.readFileSync(path.join(baseFolder, fileNames[i]));
    archive.append(stream, { name: fileNames[i] });
  }
  for (i = 0; i < folderNames.length; i++) {
    archive.directory(path.join(baseFolder, folderNames[i]), folderNames[i]);
  }

  archive.finalize(function (err, bytes) {
    if (err) throw err;
  });
}