Question

我在 MS SQL Server “MyTable”中有一个表格，如下所示 -

PkId    |    Title   |   Some Column
-----------------------------------------------
1       |    User 2  | Some value for "User 2"
-----------------------------------------------
2       |    User    | Some value for the user
-----------------------------------------------
3       |    User    | Some value for the user
-----------------------------------------------
4       |    Admin   | Some value for the Admin
-----------------------------------------------
5       |    Guest 1 | Some value for "Guest 1"
-----------------------------------------------
6       |    Guest   | Some value for the guest

我希望得到像

这样的输出

User 1 - Some value for the user
User 2 - Some value for "User 2" [Note - this "User 2" title was existing and this keeps the "Some Column" value intact as well]
User 3 - Some value for the user
Admin 1 - Some value for the Admin
Guest 1 - Some value for "Guest 1" [Note - Existing title with existing value]
Guest 2 - Some value for the guest

[我不关心订购，但是想要像上面那样映射用户，以便我可以在标题后获得数字（如果标题已经包含了跳过该编号的编号并且没有复制相同的编号） “Some Column”值保持原样]

我尝试过排名超过分区但没有达到预期的结果。请帮帮我。

Answer 1

此查询应该执行您想要的操作。这可能是有用的，正如其他人所说的那样，将用户和数字存储在这样的字符串中可能是一个好主意。

<强>查询：

// do writing
while (some condition) {
    format.writeRecord(record);
}

// finished writing
format.close();

CTE With titles as ( SELECT distinct title = title FROM @MyTable WHERE NOT RIGHT(title, 1) LIKE '[0-9]' ), numbers as ( SELECT n = ROW_NUMBER() over(PARTITION BY t.title ORDER BY pkid DESC) , pkid , Name , grp = t.title , id = TRY_PARSE(CASE WHEN d.title NOT LIKE t.title THEN RIGHT(d.title, ABS(LEN(d.title) - LEN(t.title))) END as bigint) , missing = ROW_NUMBER() over(PARTITION BY t.title, CASE WHEN d.title NOT LIKE t.title THEN 0 ELSE 1 END ORDER BY pkid DESC) FROM @MyTable d INNER JOIN titles t ON d.title LIKE t.title+'%' ), new_n as ( SELECT n, grp, id = ROW_NUMBER() over(PARTITION BY grp ORDER BY n) FROM ( SELECT n, grp FROM numbers EXCEPT SELECT id, grp FROM numbers WHERE id IS NOT NULL ) as x ) SELECT nb.pkid, n = coalesce(nb.id, nw.n), nw.grp+CAST(coalesce(nb.id, nw.n) as varchar(5)), nb.name--, * FROM numbers nb LEFT JOIN new_n nw ON nb.grp = nw.grp AND nb.missing = nw.id ORDER BY nb.pkid查找不带编号的不同标题（用户，管理员和访客）
CTE titles按组标题（n）对其进行分区，获取现有标题的ID（id）和按组标题分区，以及ID是否缺失（缺失）
CTE new_n获取每个组的未使用ID列表
最后选择将所有内容放在一起并使用现有ID或在缺少时将其替换为可用ID的1

<强>输出：

number

数据：

pkid n title name 1 2 User2 Some value for "User 2" 2 3 User3 Some value for the user 3 1 User1 Some value for the user 4 1 Admin1 Some value for the Admin 5 1 Guest1 Some value for "Guest 1" 6 2 Guest2 Some value for the guest

Answer 2

使用它：

select 'user ' + (case when patindex('%[0-9]%',title) = 0  then row_number() over (partition by title order by (select 1)) else substring(title,patindex('%[0-9]%',title),1) end) +  '-' + somecolumn
from table1

如果数字始终位于标题栏的末尾，您可以使用 -

select 'user ' + (case when isnumeric(right(title,1)) = 1 then right(title,1)  else  row_number() over (partition by title order by (select 1)) end) +  '-' + somecolumn
from table1

选择列作为唯一值sql server

2 个答案: