Question

这是来自awscli的我的JSON输出我希望仅使用AWS cli查询使用Origin DomainName example1.com 来获取 xxxxxxxx.cloudfront.net 。 {我知道用jq，awk和cut，grep}过滤。

"DistributionList": {
    "Items": [
        {
            "WebACLId": "", 
            "Origins": {
                "Items": [
                    {
                        "OriginPath": "", 
                        "CustomOriginConfig": {
                            "OriginProtocolPolicy": "http-only", 
                            "HTTPPort": 80, 
                            "HTTPSPort": 443
                        }, 
                        "Id": "DNS for Media Delivery", 
                        "DomainName": "example1.com"
                    }
                ], 
                "Quantity": 1
            }, 
            "DomainName": "xxxxxxxx.cloudfront.net", 
         },
        {
            "WebACLId": "", 
            "Origins": {
                "Items": [
                    {
                        "OriginPath": "", 
                        "CustomOriginConfig": {
                            "OriginProtocolPolicy": "http-only", 
                            "HTTPPort": 80, 
                            "HTTPSPort": 443
                        }, 
                        "Id": "DNS for Media Delivery", 
                        "DomainName": "example2.com"
                    }
                ], 
                "Quantity": 1
            }, 
            "DomainName": "yyyyyyyyyy.cloudfront.net", 
         },
       ]
    }

Answer 1

由于AWS CLI --query参数在JMESPath之上工作，您可以构建出色的过滤器。您的问题的答案将是：

--query "DistributionList.Items[].{DomainName: DomainName, OriginDomainName: Origins.Items[0].DomainName}[?contains(OriginDomainName, 'example1.com')] | [0]"

它将返回给你：

{
  "DomainName": "xxxxxxxx.cloudfront.net",
  "OriginDomainName": "example1.com"
}

P.S。希望它会帮助别人。

AWS cli查询到达cloudfront＆＃34;域名＆＃34;具体来源名称

1 个答案: