Question

如何在C＃中仅获取JSON输出值。

我正在尝试将其用于IEnumerable<IEnumerable<CustomType>>

类型

我的课程属性为IEnumerable<IEnumerable<CustomType>>

和CustomType定义为

public class CustomType{
    public string Type {get;set;}
    public string Value {get;set;}
}

var data = JsonConvert.SerializeObject(collection);

The result i am getting is 

[
    [   
        {"Type":"Role","Value":"RoleA"},
        {"Type":"Role","Value":"RoleB"}
    ],
    [
        {"Type":"Role","Value":"RoleC"}
    ],
    [
        {"Type":"Buyer","Value":"UserA"}
    ],
    [
        {"Type":"Seller","Value":"UserB"}
    ]
]

I need following output
[
    [{"Role" : "RoleA"},{"Role" : "RoleB"}],
    [{"Role" : "RoleC"}],
    [{"Buyer" : "UserA"}]       
]

Answer 1

你可以这样做，

public class CustomType
{
    public string Type { get; set; }
    public string Value { get; set; }

    public Dictionary<string, string> AsJsonProperty()
    {
        return new Dictionary<string, string>
        {
            {Type, Value}
        };
    }
}

class Class1
{
    public string ToJson(IEnumerable<IEnumerable<CustomType>> customTypes)
    {
        var asJsonFriendly = customTypes.Select(x => x.Select(y => y.AsJsonProperty()));
        return JsonConvert.SerializeObject(asJsonFriendly);
    }
}

将字典序列化为json时，它将是一个json对象（而不是数组），键将成为属性名称，值将是属性值。

这种方法特别适用于您的属性名称包含不同的字符，例如{“a property ..”：“a value”}

Answer 2

如何将CustomType转换为字典？（您不需要更改CustomType课程）

string json = JsonConvert.SerializeObject(collection.Select(innerList => 
              innerList.Select(type => new Dictionary<string,object>()
              {
                   {
                        type.Type, type.Value
                   }
              })));

Answer 3

var formatedCollections = collection.Select(c => c.Select(nest => new Dictionary<String,String>(){{nest.Type,nest.Value}})).ToArray();

然后序列化formatedCollection

获取IEnumerable <ienumerable <string>＆gt;的JSON值类型

3 个答案: