我在这里有一个关于如何实施constrOptim
的问题:
文档中的示例如下:
fQP <- function(b) {-sum(c(0,5,0)*b)+0.5*sum(b*b)}
Amat <- matrix(c(-4,-3,0,2,1,0,0,-2,1), 3, 3)
bvec <- c(-8, 2, 0)
constrOptim(c(2,-1,-1), fQP, NULL, ui = t(Amat), ci = bvec)
但是,当我将代码更改为:
时fQP <- function(b) {-sum(c(0,5,0)*b)+0.5*sum(b*b)+c}
Amat <- matrix(c(-4,-3,0,2,1,0,0,-2,1), 3, 3)
bvec <- c(-8, 2, 0)
constrOptim(c(2,-1,-1), fQP, NULL, ui = t(Amat), ci = bvec,c=5)
发生错误:
错误:
$
运算符对原子矢量无效
有人可以帮帮我吗?
答案 0 :(得分:3)
错误源于参数c=5
将control
参数与constrOptim
函数匹配,因此这与调用相同:
constrOptim(c(2,-1,-1), fQP, NULL, ui = t(Amat), ci = bvec,control=5)
# Error: $ operator is invalid for atomic vectors
control
参数希望传递一个列表但是传递5
,所以当它尝试访问元素时会引发此错误。
要使此设置有效,您需要明确声明c
是函数的参数(并进一步将其更改为不会与内置c
函数冲突的名称,你也在该功能中使用):
fQP <- function(b, c2) {-sum(c(0,5,0)*b)+0.5*sum(b*b)+c2}
Amat <- matrix(c(-4,-3,0,2,1,0,0,-2,1), 3, 3)
bvec <- c(-8, 2, 0)
constrOptim(c(2,-1,-1), fQP, NULL, ui = t(Amat), ci = bvec,c2=5)
# $par
# [1] 0.4762222 1.0475556 2.0951112
#
# $value
# [1] 2.619048
#
# $counts
# function gradient
# 506 NA
#
# $convergence
# [1] 0
#
# $message
# NULL
#
# $outer.iterations
# [1] 3
#
# $barrier.value
# [1] -0.0006243968