Question

所以，我有这个xml文件：

<Network id="TestSet01" description="Simple test set to begin development">
  <node_list>
    <node id="n0"/>
    <node id="n1"/>
    <node id="n2"/>
  </node_list>
</Network>

我有这段代码：

try {
        File inputFile = new File("TestSet01_Network.xml");
        DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
        DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
        Document doc = dBuilder.parse(inputFile);
        doc.getDocumentElement().normalize();

        NodeList rList = doc.getElementsByTagName("Network");

        for (int h = 0; h < rList.getLength(); h++) {
            Node rNode = rList.item(h);

            String name = ((Element) rNode).getAttribute("id");

            String description = ((Element) rNode).getAttribute("description");                               

            NodeList nList = ((Element) rNode).getElementsByTagName("node_list"); //Doesn't work properly here
            for (int i = 0; i < nList.getLength(); i++) {
                //code
            }
    } catch (ParserConfigurationException | SAXException | IOException e) {
    }

我遇到的问题是我似乎无法获得包含“node_list”节点的子节点的NodeList，因此我可以在之后的“for”循环中单独迭代它们。代码似乎是正确的，但列表不对。我标记了我遇到这个问题的路线。

Answer 1

 NodeList rList = doc.getElementsByTagName("Network");

将返回包含1个孩子的List：...

节点实际上是它的孩子所以你只需要在开始循环之前更深一层

Element root = doc.getDocumentElement(); //Network
            for (int i = 0; i < root.getChildNodes().getLength(); i++) {
                Node n = root.getChildNodes().item(i);
                if (n instanceof Element) {
                    NodeList nodes = n.getChildNodes();
                    for (int j = 0; j < nodes.getLength(); j++) {
                        Node theNode = nodes.item(j);
                        if (theNode instanceof Element) {
                            System.out.println(((Element) theNode).getAttribute("id"));
                        }
                    }
                }
            }

无法从java xml解析器中的当前节点获取NodeList

1 个答案: