我在匹配字符串时难以找到数据库中的重复记录。
如果你看，你会看到im selecting the comment row where the comment column equals this comment
我使用了每个评论各自的记录，但我认为我会得到2条记录2254915和50712，而他们似乎只是查询他们各自的评论。
我发现这两个查询有些不同，因为评论是相同的。
mysql> select * from comments where comment="35 dancers on the roster, but if you head in there at 4 or 5 in the afternoon, you might find 3 chicks. The only thing I'd change in this place would be the seating-the same filthy chairs for the last ten years";
+-----------+----------+---------+------------+----------+-------+--------+-----------+--------+------------+---------+--------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+-------+----------+--------+--------+
| commentid | parentid | refno | createdate | remoteip | locid | clubid | profileid | userid | legacyuser | mediaid | status | comment | likes | dislikes | import | author |
+-----------+----------+---------+------------+----------+-------+--------+-----------+--------+------------+---------+--------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+-------+----------+--------+--------+
| 2254915 | 0 | 2519833 | 1328361720 | | 3166 | 18950 | 0 | 0 | 1846155 | 0 | 1 | 35 dancers on the roster, but if you head in there at 4 or 5 in the afternoon, you might find 3 chicks. The only thing I'd change in this place would be the seating-the same filthy chairs for the last ten years | 0 | 0 | 1 | Jess |
+-----------+----------+---------+------------+----------+-------+--------+-----------+--------+------------+---------+--------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+-------+----------+--------+--------+
1 row in set (2.96 sec)
mysql> select * from comments where comment="35 dancers on the roster, but if you head in there at 4 or 5 in the afternoon, you might find 3 chicks. The only thing I'd change in this place would be the seating-the same filthy chairs for the last ten years";
+-----------+----------+---------+------------+----------+-------+--------+-----------+--------+------------+---------+--------+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+-------+----------+--------+--------+
| commentid | parentid | refno | createdate | remoteip | locid | clubid | profileid | userid | legacyuser | mediaid | status | comment | likes | dislikes | import | author |
+-----------+----------+---------+------------+----------+-------+--------+-----------+--------+------------+---------+--------+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+-------+----------+--------+--------+
| 50712 | 0 | 2519833 | 1328343720 | | 3166 | 18950 | 0 | 28128 | 0 | 0 | 1 | 35 dancers on the roster, but if you head in there at 4 or 5 in the afternoon, you might find 3 chicks. The only thing I'd change in this place would be the seating-the same filthy chairs for the last ten years | 0 | 0 | 0 | Jess |
+-----------+----------+---------+------------+----------+-------+--------+-----------+--------+------------+---------+--------+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+-------+----------+--------+--------+
1 row in set (2.39 sec)
不太清楚这里发生了什么。这是我的代码：
require_once("../www/api");
$locid=3166;
$sql="select commentid,legacyuser,userid,comment,status from comments where /**datediff(now(),from_unixtime(createdate))>=60 and*/ locid=$locid and status>=1 order by createdate desc limit 20";
$rs=mysqli_query($dbh,$sql);
$cnt=0;
while($row=mysqli_fetch_assoc($rs)){
if($cnt<10){
$cnt++;
continue;
}
$cnt++;
// variables declaration
$commentid=(int)$row['commentid'];
echo $commentid.'-';
$legacyuser=(int)$row['legacyuser'];
$userid=(int)$row['userid'];
$comment=mysqli_real_escape_string($dbh,$row['comment']);
$status=$row[status];
//echo $comment;
// get active duplicates count
//echo "select count(commentid) as count from comments where comment='$comment' and locid=608 and status!=-14"."\r\n";
$cnt=mysqli_fetch_assoc(mysqli_query($dbh,"select count(commentid) as count from comments where comment='$comment' AND locid=$locid AND status!=-14"));
$cntActive=(int)$cnt[count];
//die($cntActive);
if($cntActive==1)continue;
if($cntActive>1){
//$comment=mysqli_real_escape_string($dbh,$comment);
$activers=mysqli_query($dbh,"select commentid from comments where comment='$comment' AND locid=$locid AND status!=-14");
$icnt=0;
while($irow=mysqli_fetch_assoc($activers)){
//print_r($irow);
if($icnt==0){
$icnt++;
continue;
}
$commentid=$irow['commentid'];
echo "update comments set status=-14 where commentid=$commentid";
mysqli_query($dbh,"update comments set status=-14 where commentid=$commentid");
$icnt++;
}
}
}
从我看到它绕过计数大于1我们可以看到有2个不同的记录，但评论是相同的，所以我不知道为什么。
答案 0 :(得分：0)
两条评论不一样。第一个中有一个空格字符，而第二个空格字符。以下内容会提醒您注意这一事实，应该是您的第一个＆＃34;转到＆＃34;当两件事看起来很相似但你不确定他们是不是或不是。
SELECT MD5(comment) FROM comments WHERE commentid IN (50712,2254915);
由于空格是此处唯一的区别，您可能希望删除该空格，如下所示：
SELECT REPLACE(comment, ' ', '') FROM comments;
这绝不是近似的足够接近＆＃34;比赛。您需要为此定义更好的规则并实现自定义算法。
答案 1 :(得分：0)
仔细看一下sql语句，记录中有一个额外的空格。
import numpy as np
a = np.arange(1,11,1)
print(a)
print(a[::3])