Question

以下代码是从不同的帖子创建的，但我现在有一个单独的问题。这段代码的作用基本上是花费2个日期并从中减去周末以获得从开始到结束时间（不包括周末）的总分钟数。我现在想说的是，因为我工作一天有11个小时，所以我想每天只计算11个小时。我得到的结果如下（我添加了列名，只是让你知道它们是什么）：

@AllMins  @MinDays
2173         1.50902777777778

由于工作日有660分钟或工作日不工作780分钟，我需要从总时间中减去这个。所以，1天将是2173-780，但我也需要在当天获得.50902777777778分钟。有什么建议吗？

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '2010-08-02 00:00:00.000'
SET @EndDate = '2010-08-03 12:13:12.123'

--How many minutes are between order start and end time including non working time
DECLARE @AllMins INT 
--Declares how many minutes are in a day and makes it float to get remainder minutes when divided
DECLARE @MinsInDay FLOAT 
SET @MinsInDay = 1440

--Finds how many minutes are between start and end time excluding weekends and assignes to variable 
SET @AllMins = ((DATEDIFF(mi, @StartDate, @EndDate)) 
  -(((DATEDIFF(wk, @StartDate, @EndDate) * 2) * 24) * 60)  
  -(((CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END) * 24) * 60)
  -(((CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END) * 24) * 60)) 

--Calculates how many days have elapsed in the minutes that the order has taken
DECLARE @MinDays FLOAT
SET @MinDays = (@AllMins/@MinsInDay)

SELECT
@AllMins
,@MinDays

Answer 1

您在寻找

吗？

@AllMins - (integer portion of (@MinDays) * 780) - (fractional portion of (@MinDays) * 360)

这样你就可以从小数部分减去780分钟的部分？

SQL日期时间到分钟减去工作日.....困惑

1 个答案: