Question

我必须制作一个Android内存游戏，屏幕上会显示一系列颜色，然后你必须点击出现的颜色。要显示颜色序列，我只需使用不可更改的按钮来改变颜色。我目前正在使用runOnUiThread的线程执行此操作，但每次只将按钮更改为我想要的最后一种颜色。为什么它不会改变以前的颜色？

    final ArrayList<Integer> colours = new ArrayList<Integer>();

    Button buttonOne = (Button) findViewById(R.id.colourOne);
    Button buttonTwo = (Button) findViewById(R.id.colourTwo);
    Button buttonThree = (Button) findViewById(R.id.colourThree);
    Button buttonFour = (Button) findViewById(R.id.colourFour);

    ColorDrawable buttonOneColor = (ColorDrawable) buttonOne.getBackground();
    ColorDrawable buttonTwoColor = (ColorDrawable) buttonTwo.getBackground();
    ColorDrawable buttonThreeColor = (ColorDrawable) buttonThree.getBackground();
    ColorDrawable buttonFourColor = (ColorDrawable) buttonFour.getBackground();

    int one = buttonOneColor.getColor();
    int two = buttonTwoColor.getColor();
    int three = buttonThreeColor.getColor();
    int four = buttonFourColor.getColor();

    colours.add(one);
    colours.add(two);
    colours.add(three);
    colours.add(four);

    runOnUiThread(new Runnable() {
            @Override
            public void run() {
                for(int x = 0; x < colours.size(); x++) {
                    try {
                        Button light = (Button) findViewById((R.id.light));
                        light.setBackgroundColor(colours.get(x));
                        Thread.sleep(1000);
                    } catch (Exception e) {
                        System.out.println(e);
                    }
                }
            }
    });

线程在每个setBackground颜色之后处于休眠状态，但按钮颜色实际上不会改变，直到循环到达其最后一个循环。

Answer 1

你必须在线程调用Thread上创建一个新的runOnUiThread并更改颜色。你还必须从Thread中初始化按钮。您必须从x方法

中声明变量onCreate

new Thread(new Runnable() {
            @Override
            public void run() {
                for(x = 0; x < colours.size(); x++) {
                    runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                            light.setBackgroundColor(colours.get(x));
                        }
                    });
                    try {
                        Thread.sleep(1000);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }

            }
        }).start();

更新按钮颜色

1 个答案: