Question

我不知道这段代码是怎么回事，因为某些原因它似乎完全跳过了这个函数。

    try:
        readHandle = open(fileName, 'r')
    except IOError, ioe:
        print "Cannot open file: ", fileName,"\n"
        print "%s" %ioe
        raise

    lines = readHandle.readlines()

    lineNum = 1



    #read file line by line
    for line in lines:
        if line.startswith(':'):
            #remove : from line
            bits0 = line.partition(':')
            #remove \n newlines
            bits1 = bits0[2].partition('\n')
            #split in to an array using , as delimiter
            bits2 = bits1[0].split(',')

            DrvrNum = bits2[0]
            DrvrNam = bits2[1]

            # Debug
            if DBUG == 1:
                print "DrvrNum and DrvrNam variable values"
                print DrvrNum, DrvrNam

            crcDrvr(DrvrNum, DrvrNam)

        elif line.startswith('#'):

            #Comment line
            pass
        elif line.startswith('Ss'):
            #Crc line
            pass
        elif line.startswith('Zz'):
            #end of file
            pass

        else:
            print '\nError: line', lineNum , 'is an illegal entry'
            print '\nPlease Check'
            sys,exit(0)


        lineNum = lineNum + 1

这是被跳过的功能：

def crcDrvr(number,name):

        convNum = int(number,16)            
        convNam = ''

        for char in name:

            hexChar = char.encode("hex") 
            print hexChar

任何人都可以告诉我哪里出错导致我的代码跳过？

示例数据：

#DrvrDB
#
#    
#
Ss1234
:744,Bob Hope
:747,Testy Tester
:777,Extra Guy
:0,dummy
Zz
#Driver#,DriverName
#end of file padding 1

Answer 1

我想通了，有些天才只用变量声明创建了两次函数crcDrvr所以它一定是打了一个 - 吉姆

脚本正在跳过功能

1 个答案: