Question

在异常行之后执行行时，任何人都可以帮助编写逻辑。在代码中我捕获了异常，但我想打印行“”在异常从同一个地方捕获后不会打印“”。

public static void main(String args[]) {
    int d, a;
    try { 
    // monitor a block of code.
    d = 0;
    a = 42 / d;

    System.out.println("This will not be printed.");

    } catch (ArithmeticException e) { // catch divide-by-zero error

        System.out.println("Division by zero.");

    }

    System.out.println("After catch statement."); 

  }
}

Answer 1

bool mExceptionOccur = false;
try { 
     // monitor a block of code.
     d = 0;

     a = 42 / d;

     System.out.println("This will not be printed.");


} catch (ArithmeticException e) { // catch divide-by-zero error
    mExceptionOccur = true;
    System.out.println("Division by zero.");

}finally{
    if (mExceptionOccur)
        System.out.println("After catch statement.  Exception Occurred"); 
    else
        System.out.println("After catch statement.  No Exception Occurred"); 
}

使用try-catch-finally语句。无论是否捕获到异常，都将始终执行finally部分。

通过添加变量，您可以监视在执行finally部分之前是否抛出了异常。

Answer 2

怎么样：

 public static void main(String args[]) {
        int d, a;
        try { 
        // monitor a block of code.

        System.out.println("This will not be printed.");

        d = 0;

        a = 42 / d;




        } catch (ArithmeticException e) { // catch divide-by-zero error

            System.out.println("Division by zero.");

        }

        System.out.println("After catch statement."); 
    }

    }

任何人都可以帮助在异常行之后执行行中写入逻辑

2 个答案: