Question

我的这个功能有问题

$priv_key = openssl_pkey_get_private(file_get_contents("server.pem"));

$keyData = openssl_pkey_get_details($priv_key);

$keyData['key'] = str_replace('-----BEGIN PRIVATE KEY-----', '', $keyData['key']);
$keyData['key']= trim(str_replace('-----END PRIVATE KEY-----','',$keyData['key']));

echo $keyData['key'];

它应该返回私钥，但它给了我这个错误

警告：openssl_pkey_get_details（）期望参数1为资源，布尔值第14行的C：\ Users \ User \ Desktop \ xampp \ htdocs \ chiaveP.php

我该如何解决这个问题？

Answer 1

我不确定您的评论是否尝试回显server.pem文件的内容失败，或者您是否意味着整个脚本。希望下面的代码有助于确定问题的位置！

<?php

    $debug=true;
    $cert='/full/path/to/server.pem';/* this should be outside the document root */
    $keytype='PRIVATE KEY';/* this is here because in testing I have an `RSA PRIVATE KEY` */


    if( realpath( $cert ) ){
        /* The file exists at the path given: read the contents */

        $priv_key = openssl_pkey_get_private( file_get_contents( realpath( $cert ) ) );

        if( $priv_key ) {

            $keyData = openssl_pkey_get_details( $priv_key );

            $keyData['key'] = str_replace( '-----BEGIN '.$keytype.'-----', '', $keyData['key'] );
            $keyData['key'] = trim( str_replace( '-----END '.$keytype.'-----','',$keyData['key'] ) );   

            echo $keyData['key'];   
        } else {
            echo $debug ? 'failed to read private key' : 'error #1';
        }
    } else {
        echo $debug ? 'unable to find ' . $cert : 'error #2';   
    }

?>

作为一种可能的替代方法，正如您所说.pem文件与php脚本位于同一目录中，也许可以尝试：

$data=file_get_contents(realpath(__DIR__.DIRECTORY_SEPARATOR.'server.pem'));
echo $debug ? $data : '';
$priv_key = openssl_pkey_get_private( $data );

/*
    I tried using the path ( `c:/wwwroot/certificates/server.pem` ) as the parameter to the
    `openssl_pkey_get_private` rather than actually reading the contents into a string 
    but that failed. The method above however worked for me when the cert was in the same dir.
*/

Answer 2

你必须在openssl_pkey_get_private()上收到错误，因为它明显返回一个布尔值false。来自文档：

成功时返回正键资源标识符，错误时返回FALSE。

当方法在出错时返回false时，最好对其进行检查，因为它会使代码更容易调试。

私钥与PHP和＆＃34; openssl_pkey_get_details（）期望参数1是资源＆＃34;

2 个答案: