我正在尝试使用硬编码字符串构建数据文件...
所以我使用的是这种格式:
Format: %a1s%06c%a20s%a30s%a30s%a30s%a30s%a7s%a13s%a20s%a8s%a1s%a1s%a1s%a30s%a14s%a1s%a2s%a39s%a8s%a30s%a2s%a13s%a5s%a7s%a1s%a8s%03c
Values: "A", "16", "", "", "Ola Nordmann", "Slottsgate 1", "", "1012", "", "", "", "", "", "P", "", "", "I", "", "", "", "", "", "", "", "", "", "", ""
Output: "1s20s30s30s30s30s7s13s20s8s1s1s1s30s14s1s2s39s8s30s2s13s5s7s1s8s"
我的代码:
$aRecord = vsprintf($format, $values);
return ['a-record' => $aRecord, 'values' => $values, 'format' => $format];
可能只是因为它非常晚和周五下午,希望你们中的一些人能解决我的错误......谢谢! :)
编辑:
预期产出:
A000016 Ola Nordmann Slottsgate 1 1012
答案 0 :(得分:0)
所以解决方案非常简单:P
对于左对齐文字,我们需要使用-
代替a
printf("% -20s", "Richard");
希望这有助于某人:)