Question

我正在尝试使用django视图测试ajax的使用。我是ajax和django的新手。我创建了一个3 * 3按钮单元的网格。当我单击任何按钮时，它会用'X'替换它的文本，然后在ajax的帮助下传递给查看“handler”。但是在我的情况下，它没有传递控件来查看“处理程序”。我不明白为什么它不起作用。这是我的代码：

url file：

 from django.conf.urls import include, url
    from django.contrib import admin
    from game import views
    urlpatterns = [
        url(r'^admin/', admin.site.urls),
        url(r'^handler/',views.handler,name='handler'),
        url(r'^$',views.home,name='home'),
    ]

观看档案

from django.shortcuts import render
    from django.http import HttpResponse
    from django.http import Http404

    def handler(request):
        if request.is_ajax():
            pos = request.POST['pos']
            return HttpResponse(2)
        else:
            raise Http404
    def home(request):
        context = {}
        return render(request,"game/home.html",context)

home.html文件：

<head>
<head>
<style>
td {
    padding:0;
}
table {
    height:240px;
    width:240px;
    border-collapse: collapse;
    border-spacing: 0
}
input {
    margin:0;
    width:80px;
    height:80px;
    font-size: 50px;
    text-align: center;
}
#content {
    position:absolute;
    top:210px;
    left:540px;
}
</style>
<script>
function change(id)
{
    var y = document.getElementById(id);
    y.value = 'X';
    $.ajax({
        url:"handler/",
        type:"POST",
        data:{pos:id},

        success:function(data) {
            var x = document.getElementById(data);
            x.value = 'O';
            console.log("sucess");
        },
        error:function(xhr,errmsg,err) {
            alert("error");
        }
    });
}
</script>
</head>
<body>
<div id = "content">
<center><table>
<tr>
<td><input type = "button" onclick="change(1)" id = "1"></input></td>
<td><input type = "button" onclick="change(2)" id = "2"></input></td>
<td><input type = "button" onclick="change(3)" id = "3"></input></td>
</tr>
<tr>
<td><input type = "button" onclick="change(4)" id = "4"></input></td>
<td><input type = "button" onclick="change(5)" id = "5"></input></td>
<td><input type = "button" onclick="change(6)" id = "6"></input></td>
</tr>
<tr>
<td><input type = "button" onclick="change(7)" id = "7"></input></td>
<td><input type = "button" onclick="change(8)" id = "8"></input></td>
<td><input type = "button" onclick="change(9)" id = "9"></input></td>
</tr>
</table>
</center>
</div>
</body>
</html>

Answer 1

使用csrf_exempt装饰器，因为你没有通过ajax发送csrf令牌。此外，请确保已将<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>包含在模板文件中。这应该有用。

from django.views.decorators.csrf import csrf_exempt
from django.shortcuts import render
from django.http import HttpResponse
from django.http import Http404

@csrf_exempt
def handler(request):
    if request.is_ajax():
        pos = request.POST['pos']
        return HttpResponse(2)
    else:
        raise Http404

使用带有django的ajax来传递信息

1 个答案: