Question

这里我有一些json code.with 2 dict of data.like

name1
name2
lap1
lap2

只有label1，label2显示值。 Label3，label4没有显示值！

Answer 1

使用此

NSArray *jsonObject;
jsonObject = @[@{@"Id1":@"mad",
                 @"people2":@"12",@"total2":@"20"},
               @{@"Id2":@"normal",
                 @"people3":@"13",@"total3":@"30"}];


NSData *jsonData = [NSJSONSerialization dataWithJSONObject:jsonObject options:NSJSONWritingPrettyPrinted error:nil];
NSError *error = nil;
NSArray *arr = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableContainers error:&error];

NSLog(@" JSON DATA \n  %@",arr);


for (int i = 0; i < arr.count; i++) {

    NSArray *keys = [[arr objectAtIndex:i] allKeys];
    NSLog(@"%@",[[arr objectAtIndex:i] valueForKey:[keys objectAtIndex:0]]);
    NSLog(@"%@",[[arr objectAtIndex:i] valueForKey:[keys objectAtIndex:1]]);
    NSLog(@"%@",[[arr objectAtIndex:i] valueForKey:[keys objectAtIndex:2]]);
    //assign your label here line yourLabel.text = [[arr objectAtIndex:i] valueForKey:[keys objectAtIndex:0]];
}

注意：它适用于有3个键的字典

Answer 2

NSData＆＃39; jsonData＆＃39;不可遍历，但您可以遍历jsonObject，即包含字典对象的NSArray。

label1.text = [jsonObject[0] objectForKey:@"people1"];
label2.text = [jsonObject[0] objectForKey:@"total1"];
label3.text = [jsonObject[1] objectForKey:@"people2"];
label4.text = [jsonObject[1] objectForKey:@"total2"];

Answer 3

使用此代码：

label1.text = [[jsonObject objectAtIndex:0] valueForKey:@"people2"];
label2.text = [[jsonObject objectAtIndex:0] valueForKey:@"total2"];
label3.text = [[jsonObject objectAtIndex:1] valueForKey:@"people3"];
label4.text = [[jsonObject objectAtIndex:1] valueForKey:@"total3"];

Answer 4

你的错！你在jsonArray中有2个词典

 NSDictionary *dict = [jsonArray objectAtIndex:0];

 NSDictionary *dict2 = [jsonArray objectAtIndex:1];

NSLog(@"%@",[dict valueForKey:@"people1"]);
NSLog(@"%@",[dict valueForKey:@"total1"]);
NSLog(@"%@",[dict2 valueForKey:@"people2"]);
NSLog(@"%@",[dict2 valueForKey:@"total2"]);

将json值指定给label

4 个答案: