除非他们知道用户名和密码,否则我写了一个程序让用户不在场。它只是我为了好玩而写的一个程序,并没有真正有用的目的。但是,在测试代码时,我注意到在尝试从最近写入的文件中读取时出现问题。无论出于何种原因,我为username.txt文件创建的扫描程序对象userOut都没有检测到它们是文件中的任何内容(即.hasNextLine()返回false),但仅如果它写在程序中。如果我写一些文本到文件,然后运行程序,它工作得很好。请注意,password.txt文件完全正常。为什么会这样?
这是我的代码:
import java.io.File;
import java.io.FileOutputStream;
import java.io.PrintWriter;
import java.util.Scanner;
public class Challenge5 {
public static void main(String[] args) {
try {
File usernameFile = new File("username.txt");
File passwordFile = new File("password.txt");
PrintWriter userOut = new PrintWriter(new FileOutputStream(usernameFile, true));
PrintWriter passOut = new PrintWriter(new FileOutputStream(passwordFile, true));
Scanner in = new Scanner(System.in);
Scanner userIn = new Scanner(usernameFile, "UTF-8");
Scanner passIn = new Scanner(passwordFile, "UTF-8");
System.out.println("Welcome to Luke's secure program.");
if (!userIn.hasNextLine() || !userIn.hasNextLine()) {
System.out.println("New users must set up their account: ");
if (!userIn.hasNextLine()) {
System.out.print("Enter a username: ");
String username = in.nextLine().trim();
userOut.print(username);
userOut.flush();
}
if (!userIn.hasNextLine()) {
System.out.print("Enter a password: ");
String password = in.nextLine().trim();
passOut.print(password);
passOut.flush();
}
System.out.println("Your account has been created. You may now log in:");
}
System.out.print("Please enter username: ");
String username = in.nextLine().trim();
System.out.print("Please enter password: ");
String password = in.nextLine().trim();
String fileUsername = "";
while (userIn.hasNextLine()) {
fileUsername = userIn.nextLine();
}
System.out.println(fileUsername);
String filePassword = "";
while (passIn.hasNextLine()) {
filePassword = passIn.nextLine();
}
System.out.println(filePassword);
if (username.equals(fileUsername) && password.equals(filePassword)) {
System.out.println("Welcome!");
while (true) {
System.out.println("What would you like to do? ");
System.out.println("1. Change username\n2. Change password\n3. Exit");
System.out.print("> ");
int choice;
while (!in.hasNextInt()) {
System.out.println("What would you like to do? ");
System.out.println("1. Change username\n2. Change password\n3. Exit");
System.out.print("> ");
in.next();
}
choice = in.nextInt();
in.nextLine();
if (choice == 1) {
userOut = new PrintWriter(new FileOutputStream(usernameFile, false));
System.out.print("Enter new username: ");
String newUsername = in.nextLine().trim();
userOut.print(newUsername);
userOut.flush();
} else if (choice == 2) {
passOut = new PrintWriter(new FileOutputStream(passwordFile, false));;
System.out.print("Enter new password: ");
String newPassword = in.nextLine().trim();
passOut.print(newPassword);
passOut.flush();
} else if (choice == 3) {
System.out.println("Goodbye!");
break;
} else {
System.out.println("Please try again.");
}
}
} else {
System.out.println("INVALID USERNAME OR PASSWORD, EXITING PROGRAM...");
}
userOut.close();
passOut.close();
in.close();
userIn.close();
passIn.close();
} catch (Exception ex) {
ex.printStackTrace();
}
}
}
我认为我的代码并不完美,但我认为它至少应该起作用。任何帮助将不胜感激。
答案 0 :(得分:0)
您需要重新初始化您的扫描仪对象,以打开更新文件内容的输入流。
System.out.print("Please enter password: ");
String password = in.nextLine().trim();
在上面两行之后,您需要以下内容:
userIn = new Scanner(usernameFile, "UTF-8");
passIn = new Scanner(passwordFile, "UTF-8");
您无法读取任何内容的原因是因为当文件中没有任何内容时,您使用userIn
和passIn
打开文件用户名和密码的输入流连接。添加以上两行打开与更新文件的新输入流连接,因此,您将能够阅读内容。
您似乎对以下条件存在一些问题:
//if (!userIn.hasNextLine() || !userIn.hasNextLine()) {
if (!userIn.hasNextLine() || !passIn.hasNextLine()) {
System.out.println("New users must set up their account: ");
if (!userIn.hasNextLine()) {
System.out.print("Enter a username: ");
String username = in.nextLine().trim();
userOut.print(username);
userOut.flush();
}
//why again !userIn.hasNextLine(), you should check passIn
//if (!userIn.hasNextLine()) {
if (!passIn.hasNextLine()) {
System.out.print("Enter a password: ");
String password = in.nextLine().trim();
passOut.print(password);
passOut.flush();
}
System.out.println("Your account has been created. You may now log in:");
}
我修复了这两个条件并注释掉了你的代码位。