Question

我正在用Python编写服务器，客户端将发送命令（通过命令行arg）＆＃34; BYE＆＃34;。此时应终止客户端/服务器之间的连接。（我认为socket.close（）会终止连接，但我不完全确定这是否正确）

我写了一个改编的echo服务器，其中的clientsocket.close（）在服务器迭代结束时。我希望只有收到BYE才能发生这种情况。

我不确定我的服务器程序的结构是否导致了问题（我还没有使用getopt - 因为我仍然需要弄明白）

服务器：

from multiprocessing import Process
import socket
import os

def handler(clientsocket, clientaddr):
    print "Accepted connection from: ", clientaddr
    while 1:
        data = clientsocket.recv(1024)
        if data:
            if data == "BYE":
                print "recvd BYE"
                clientsocket.send("BYE")
                clientsocket.close()
#                p.join()
            elif data == "DIR":
                print "recvd DIR"
                DIR = os.getcwd()
                clientsocket.send(DIR)

            print "data recieved:"
            print data
            msg = "You sent me: %s" % data
            clientsocket.send(msg)
            clientsocket.close()
            return

if __name__ == "__main__":

    TCP_IP = '127.0.0.1'
    TCP_PORT = 5004
    BUFFER_SIZE = 1024

    print 'socket()'
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

    print 'bind()'
    s.bind((TCP_IP, TCP_PORT))

#    f = open('recv.txt', 'wb')

    print 'listen()'
    s.listen(5)

    workerProcesses =[]

    while 1:
        print "Server is listening for connections\n"
        clientsocket, clientaddr = s.accept()
        p = Process(target=handler, args = (clientsocket, clientaddr))
        p.start()
#        p.join()
        workerProcesses.append(p)

    serversocket.close()

当我将我的clientsocket.close（）放入if＆＃34; BYE＆＃34;声明，我得到错误：错误的套接字描述符。服务器的输出是：

data recieved:
BYE
Process Process-1:
Traceback (most recent call last):
  File "/usr/lib64/python2.6/multiprocessing/process.py", line 232, in _bootstrap
    self.run()
  File "/usr/lib64/python2.6/multiprocessing/process.py", line 88, in run
    self._target(*self._args, **self._kwargs)
  File "pyServ.py", line 26, in handler
    clientsocket.send(msg)
  File "/usr/lib64/python2.6/socket.py", line 167, in _dummy
    raise error(EBADF, 'Bad file descriptor')
error: [Errno 9] Bad file descriptor

关于为什么会发生这种情况的任何想法？

Answer 1

你的handler（）函数中有

：

       if data == "BYE":
            print "recvd BYE"
            clientsocket.send("BYE")
            clientsocket.close()
            #p.join()
        elif data == "DIR":
            print "recvd DIR"
            DIR = os.getcwd()
            clientsocket.send(DIR)

        print "data recieved:"
        print data
        msg = "You sent me: %s" % data
        clientsocket.send(msg)
        clientsocket.close()
        return

如果data == "BYE"那么你发送＆＃34; BYE＆＃34;并关闭你的插座...然后你打印＆＃34;收到的数据＆＃34; （错字）：）

然后在close()语句中调用if。一旦超出if语句，您就会在刚关闭的套接字上再次尝试send()数据。关闭套接字后，文件句柄不再有效。你需要修改你的代码，这样就不会发送一个封闭的套接字......我看到了两种明显的方式。

应

        if data == "BYE":
            print "recvd BYE"
            clientsocket.send("BYE")
            clientsocket.close()
            #p.join()
        elif data == "DIR":
            print "recvd DIR"
            DIR = os.getcwd()
            clientsocket.send(DIR)

        print "data recieved:"
        print data
        return

或

删除if语句
中对clientsocket.close（）的调用

Python多重处理/套接字 - 错误的文件描述符

1 个答案: