Symfony2-Cropit |如何取回我的裁剪图像？

Question

我非常对这个插件感到失望。我是JS / Jquery的一个菜鸟但是我非常需要这个插件用于我的网站...... 所以我在这里找到了cropit：http://scottcheng.github.io/cropit/

我不知道如何在我的控制器中取回我的裁剪图像并保存... 所以我的表格是：

<div class="form-group">
    {{ form_label(form.image, 'Image', {'label_attr': {'class': 'col-sm-3 control-label'}})}}
      <div class="image-cropper">
           <!-- This is where the preview image is displayed -->
          <div class="row">
            <div class="col-sm-offset-2 col-sm-8">
              <div class="cropit-image-preview-container">
               <div class="cropit-image-preview"></div>
             </div>
           </div>
         </div> 
                <!-- This range input controls zoom -->
                    <!-- You can add additional elements here, e.g. the image icons -->
          <div class="row">
            <div class="col-sm-offset-4 col-sm-4">
              <input type="range" class="cropit-image-zoom-input" />
            </div>
          </div>
              {{ form_errors(form.image) }}

          <div class="row">    
            <div class="col-sm-4">
              {{ form_widget(form.image) }}
                <div class="select-image-btn">Select new image</div>
                <div class="send_image">Get Cropped image.</div>
            </div>
          </div>
      </div>
</div>

我的Jquery代码：

    <script src="http://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<script type="text/javascript" src="{{ asset('js/cropit-master/dist/jquery.cropit.js') }}"></script>

<script>
 $(function () {
     $('.select-image-btn').click(function(){
         $('.cropit-image-input').click();
    });


      var z = $('.image-cropper');
      z.cropit({
          exportZoom: 0.5,
          imageBackground: true,
          imageBackgroundBorderWidth: 15
      });
      $('.send_image').click(function() {
            var h =z.cropit('export');
            alert(h);
       });
   });
</script>

我的Image.php实体：

     public function getFile()
  {
    return $this->file;
  }

  public function setFile(UploadedFile $file = null)
  {
    $decoded = urldecode($file);
    $exp = explode(';', $decoded);
    $exp = explode(':', $exp[0]);
    $data = array_pop($exp);
    $this->file = imagecreatefromstring($file);


    if (null !== $this->url) {
      $this->tempFilename = $this->url;

      $this->url = null;
      $this->alt = null;
    }
  }

  /**
   * @ORM\PrePersist()
   * @ORM\PreUpdate()
   */
  public function preUpload()
  {

    if (null === $this->file) {
      return;
    }


    $this->url = $this->file->guessExtension();


    $this->alt = $this->file->getClientOriginalName();
 }

  /**
   * @ORM\PostPersist()
   * @ORM\PostUpdate()
   */
  public function upload()
  {

    if (null === $this->file) {
      return;
    }


    if (null !== $this->tempFilename) {
      $oldFile = $this->getUploadRootDir().'/'.$this->id.'.'.$this->tempFilename;
      if (file_exists($oldFile)) {
        unlink($oldFile);
      }
    }


    $this->file->move(
      $this->getUploadRootDir(), // Le répertoire de destination
      $this->id.'.'.$this->url   // Le nom du fichier à créer, ici « id.extension »
    );
  }

  /**
   * @ORM\PreRemove()
   */
  public function preRemoveUpload()
  {
    $this->tempFilename = $this->getUploadRootDir().'/'.$this->id.'.'.$this->url;
  }

  /**
   * @ORM\PostRemove()
   */
  public function removeUpload()
  {
    if (file_exists($this->tempFilename)) {
      // On supprime le fichier
      unlink($this->tempFilename);
    }
  }

  public function getUploadDir()
  {
    // On retourne le chemin relatif vers l'image pour un navigateur
    return 'uploads/img';
  }

  protected function getUploadRootDir()
  {
    // On retourne le chemin relatif vers l'image pour notre code PHP
    return __DIR__.'/../../../../web/'.$this->getUploadDir();
  }

  public function getWebPath()
  {
    return $this->getUploadDir().'/'.$this->getId().'.'.$this->getUrl();
  }

我看过很多帖子，但没有什么对我有用，我也不太了解。 那么有人可以帮我解释一下吗？ 谢谢

编辑：我的第一种方法

我的表单中有一个隐藏的输入来保存base64数据：

 $('form').submit(function() {
        // Move cropped image data to hidden input
        var imageData = $('.image-cropper').cropit('export');
        $('.hidden-image-data').val(imageData);
      };``

和我的Imagetype带有文件输入以加载原始图像和隐藏输入以保存base64图像。

 public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('file', 'file', array(
                'attr' => array('class' => 'cropit-image-input')))
            ->add('file', 'hidden', array('attr' => array('class' => 'hidden-image-data')))

        ;
    }

我的控制器仍然是一样的。

Answer 1

我已经解决了。

另外使用VichUploaderBundle

@ K-Phoen响应对指导解决方案非常有用。 VichUploaderBundle & Cropit - Pass base64 to a File instance

这是我的代码：

User.php ，这个以及更多VichUploaderBundle设置look here

namespace Application\Sonata\UserBundle\Entity;

//...
use Vich\UploaderBundle\Mapping\Annotation as Vich;

/**
 * User
 *
 * ........
 * ........
 * @Vich\Uploadable
 * ........
 * ........
 * 
 */
class User extends BaseUser {

    /**
     * NOTE: This is not a mapped field of entity metadata, just a simple property.
     * 
     * @Vich\UploadableField(mapping="user_avatar", fileNameProperty="avatarName")
     * 
     * @var File
     */
    private $avatar;

    /**
     * @ORM\Column(type="string", length=255)
     *
     * @var string
     */
    private $avatarName;

    /**
     * @ORM\Column(type="datetime")
     *
     * @var \DateTime
     */
    private $updatedAt;

    //....


    /**
     * If manually uploading a file (i.e. not using Symfony Form) ensure an instance
     * of 'UploadedFile' is injected into this setter to trigger the  update. If this
     * bundle's configuration parameter 'inject_on_load' is set to 'true' this setter
     * must be able to accept an instance of 'File' as the bundle will inject one here
     * during Doctrine hydration.
     *
     * @param File|\Symfony\Component\HttpFoundation\File\UploadedFile $image
     */
    public function setAvatar(File $image = null) {
        $this->avatar= $image;

        if ($image) {
            // It is required that at least one field changes if you are using doctrine
            // otherwise the event listeners won't be called and the file is lost
            $this->updatedAt = new \DateTime('now');
        }
    }

    /**
     * @return File
     */
    public function getAvatar() {
        return $this->avatar;
    }

    /**
     * @param string $avatarName
     */
    public function setAvatarName($avatarName) {
        $this->avatarName= $avatarName;
    }

    /**
     * @return string
     */
    public function getAvatarName() {
        return $this->avatarName;
    }

}

<强> UserType.php

namespace AppBundle\Form;

//...
use Doctrine\Common\Persistence\ObjectManager;
use AppBundle\Form\DataTransformer\ImageStringToFileTransformer;

class UserType extends AbstractType {

    private $manager;

    public function __construct(ObjectManager $manager)
    {
        $this->manager = $manager;
    }

    /**
     * @param FormBuilderInterface $builder
     * @param array $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options) {
        $builder                
            ->add('avatar', 'hidden', [
                'attr' => [
                    'class' => 'hidden-image-data'
                ]
            ])
            ->add('imagedata', 'file', [
                'mapped' => false,
                'required' => false,
                'attr' => [
                    'class' => 'cropit-image-input'
                ]
            ])
            //...
            ;

        $builder->get('avatar')
            ->addModelTransformer(new ImageStringToFileTransformer($this->manager));
    }

    //...

}

ImageStringToFileTransformer.php ，这里完成了魔术，我们将base64字符串转换为UploadedFile

namespace AppBundle\Form\DataTransformer;

use Symfony\Component\Form\DataTransformerInterface;
use Doctrine\Common\Persistence\ObjectManager;
use Symfony\Component\HttpFoundation\File\UploadedFile;

/**
 * Description of ImageStringToFileTransformer
 *
 * @author Juanjo García
 */
class ImageStringToFileTransformer implements DataTransformerInterface {

    private $manager;

    public function __construct(ObjectManager $manager) {
        $this->manager = $manager;
    }

    /**
     * Transforms a string (base64) to an object (File).
     *
     * @param  string $imageString
     * @return File|null
     * @throws TransformationFailedException if no object (File)
     */
    public function reverseTransform($imageString) {

        // no base64? It's optional, so that's ok       
        if (!$imageString) {
            return;
        }

        preg_match('/data:([^;]*);base64,(.*)/', $imageString, $matches);

        $mimeType = $matches[1];
        $imagenDecodificada = base64_decode($matches[2]);
        $filePath = sys_get_temp_dir() . "/" . uniqid() . '.png';
        file_put_contents($filePath, $imagenDecodificada);

        $file = new UploadedFile($filePath, "user.png", $mimeType, null, null, true);

        if (null === $file) {
            // causes a validation error
            // this message is not shown to the user
            // see the invalid_message option
            throw new TransformationFailedException(sprintf(
                 'An issue with number "%s" does not exist!', $imageString
            ));
        }

        return $file;
    }

    /**
     * Transforms an object (File) to a string (base64).
     *
     * @param  File|null $file
     * @return string
     */
    public function transform($file) {
        return '';
    }

}

<强> services.yml

services:

    # datatransformer before saving to image
    app.form.type.user:
        class: AppBundle\Form\UserType
        arguments: 
            entityManager: "@doctrine.orm.entity_manager"
        tags:
            - 
                name: form.type

在我的树枝上， 的 my_form.html.twig

<script src="{{ asset('jquery.js') }}"></script>
<script src="{{ asset('jquery.cropit.js') }}"></script>
<script src="{{ asset('jquery.custom.js') }}"></script>

{% form_theme form with ['AppBundle:Forms:vich_cropit_fields.html.twig'] %}

{{ form_start(form, {'action': path('the_path'), 'method': 'POST', 'multipart': true, 'attr': {'class': 'the_class', 'role': 'form'} }) }}
    <div class="image-editor">
        <div class="cropit-image-preview-container">
            <div class="cropit-image-preview"></div>
        </div>
        {{ form_widget(form.avatar) }}
        {{ form_widget(form.imagedata) }} 
        <div class="image-size-label">
        Resize image
        </div>
        <input type="range" class="cropit-image-zoom-input">
        {% if app.user.avatarName %}
            <img src="{{ vich_uploader_asset(app.user, 'avatar') }}" id="current-avatar" class="hide" />
        {% endif %}
    </div>   

    {{ form_rest(form) }}       

    <button type="submit" name="submit">Save</button>  

{{ form_end(form) }}

init Cropit， jquery.custom.js

(function ($) {

    $('.image-editor').cropit({
          exportZoom: 0.5,
          imageBackground: true,
          imageBackgroundBorderWidth: 50
      });

    $('.image-editor').cropit('imageSrc', $("#current-avatar").attr('src'));

    $('form').submit(function () {
        // Move cropped image data to hidden input
        var imageData = $('.image-editor').cropit('export');
        $('.hidden-image-data').val(imageData);
    });

}).apply(this, [jQuery]);

由于我在任何地方都找不到解决方案的答案，所以我决定离开这里，为每个需要它的人。我希望你能发现它有所帮助。

Answer 2

获取已保存文件的路径：

<?php
public function getUploadedFilePath()
{
    return $this->getUploadRootDir().'/'.$this->id.'.'.$this->tempFilename;
}

尝试在copit页面上获取图像数据：

<script>
var h = $imageCropper.cropit('export', {
  type: 'image/jpeg',
  quality: .9,
  originalSize: true
});
</script>