Question

我可能错过了一些小东西，但我找不到它。使用file.getFileName（）。endsWith（“。mp3”），布尔值始终为false。如果我将te文件重命名为* .mp并将代码更改为endsWith（“。mp”），则会找到它们。这里发生了什么？

问候， Jelmew

编辑：文件是路径对象btw。

文件名：

/home/jelmer/Music/01 - Nightwish - Shudder Before The Beautiful.mp3
/home/jelmer/Music/02 - Nightwish - Weak Fantasy.mp3
/home/jelmer/Music/03 - Elan (Album Version).mp3
/home/jelmer/Music/04- Nightwish - Yours Is An Empty Hope.mp3
/home/jelmer/Music/05 - Nightwish - Our Decades In The Sun.mp3
/home/jelmer/Music/06 - Nightwish - My Walden.mp3
/home/jelmer/Music/07 - Nightwish - Endless Forms Most Beautiful.mp3
/home/jelmer/Music/08 - Nightwish - Edema Ruh.mp3
/home/jelmer/Music/09 - Nightwish - Alpenglow.mp3
/home/jelmer/Music/10 - Nightwish - Eyes Of Sharbat Gula.mp3
/home/jelmer/Music/11 - Nightwish - The Greatest Show on Earth.mp3
/home/jelmer/Music/test.mp3


public class mp3Walker extends SimpleFileVisitor<Path> {

    public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
        if(file.getFileName().endsWith(".mp3")) {
            System.out.println(file);
        }
        System.out.println("done with file: "+file.getFileName());
        return FileVisitResult.CONTINUE;
    }

    public static void main(String[] args) throws IOException {
        mp3Walker walker= new mp3Walker();
        Files.walkFileTree(Paths.get("/home/jelmer/Music/"), walker);
    }
}

输出：

done with file: 07 - Nightwish - Endless Forms Most Beautiful.mp3
done with file: test.mp3
done with file: 08 - Nightwish - Edema Ruh.mp3
done with file: 05 - Nightwish - Our Decades In The Sun.mp3
done with file: 02 - Nightwish - Weak Fantasy.mp3
done with file: 11 - Nightwish - The Greatest Show on Earth.mp3
done with file: 01 - Nightwish - Shudder Before The Beautiful.mp3
done with file: 10 - Nightwish - Eyes Of Sharbat Gula.mp3
done with file: 04- Nightwish - Yours Is An Empty Hope.mp3
done with file: 06 - Nightwish - My Walden.mp3
done with file: 03 - Elan (Album Version).mp3
done with file: 09 - Nightwish - Alpenglow.mp3

Answer 1

这是因为Path＆＃39; .endsWith()期望路径的完整元素。

那是：

Paths.get("foo").endsWith("oo")

相当于：

Paths.get("foo").endsWith(Paths.get("oo"))

总是返回false。

您想测试文件名的字符串值：

path.getFileName().toString().endsWith(".mp3")

Answer 2

Path.getFileName（）提供了一个Path对象 - 而不是String，正如您所期望的那样。和Path.endsWith（String）：

测试此路径是否以＆＃34; Path＆＃34;结束，通过转换给定的路径字符串构造，完全按照＆＃34; endsWith（Path）＆＃34;指定的方式。方法。例如，在UNIX上，路径＆＃34; foo / bar＆＃34;结束于＆＃34; foo / bar＆＃34; ＆＆＃34; bar＆＃34;。它不会以＆＃34; r＆＃34;或＆＃34; / bar＆＃34;

也许你需要处理＆＃34; toString＆＃34;表示：

file.getFileName（）的toString（）的endsWith（＆＃34; .MP3＆＃34）。

file.getFileName（）。endsWith（）没有检测到.mp3

2 个答案: