Question

我必须在点击MenuItem时显示一个Popup。我已经写了下面的代码：

<ContextMenu>
    <Border>
        <MenuItem Name="ack" Header="ACK" HorizontalAlignment="Center" Command="{Binding AcknowledgeCommand}"  Visibility="{Binding IsAcked, Converter={StaticResource showOnFalse}}" Click="MenuItem_Click_1"/>
    </Border>
    <Separator/>
    <Border>
        <MenuItem Header="Info" HorizontalAlignment="Center" Click="MenuItem_Click"/>
    </Border>
    <Separator/>
    <Border>
        <MenuItem Header="Goto" HorizontalAlignment="Center"/>
    </Border>
    <Popup Name="infoPopup" Placement="Mouse" HorizontalOffset="-100" VerticalOffset="-100" AllowsTransparency="True" StaysOpen="True">
        <Alarms:UserControl_MYUC DataContext="{Binding TopMost}" Background="{DynamicResource DetailPanelCompartmentTitleBg}" BorderBrush="{DynamicResource SecWindowBtnBorder}"/>
    </Popup>
</ContextMenu>

OnClick的MenuItem，我写了以下代码：

private void MenuItem_Click(object sender, RoutedEventArgs e)
{
    infoPopup.Visibility = System.Windows.Visibility.Visible;
    infoPopup.IsOpen = true;
}

我可以在点击“信息”按钮时看到弹出窗口，但弹出窗口会在一秒钟内完成。我希望它可见，直到用户点击其他区域或弹出窗口失去焦点。请建议做什么。

Answer 1

将Target = BindingTarget.Type应用于您的MenuItem。

Answer 2

请使用StaysOpen布尔来定义您想要的内容。

myPopup.StaysOpen = true;

有关详细信息，请参阅以下链接：https://msdn.microsoft.com/en-us/library/system.windows.controls.primitives.popup.staysopen(v=vs.110).aspx

Popup无法在MenuItem上运行

2 个答案: