使用for循环设置变量

时间:2015-11-24 13:50:35

标签: linux bash shell loops scripting

我似乎无法在我的shell脚本中分配一堆变量。我试图将HOST1,HOST2,HOST3分配给三个不同的机器名称。

我的脚本如下:

   #!/bin/bash
   #
   set -vx

   FIXHOSTS=`cat /tmp/fixHosts.txt`
   NUMBER=1
   NUMBEROFHOSTS=`cat /tmp/fixHosts.txt | wc -l`

   for line in $FIXHOSTS
   do 
   HOST$NUMBER=$line
   echo $HOST1
   ((NUMBER = $NUMBER + 1)) 
   done

   echo $HOST1
   echo $HOST2
   echo $HOST3
   echo $HOST4

fixHosts.txt包含以下内容:

      wayne-000
      wayne-002
      wayne-003

这是我得到的输出:

for line in $FIXHOSTS
do 
HOST$NUMBER=$line
echo $HOST1
((NUMBER = $NUMBER + 1))
done
+ for line in '$FIXHOSTS'
+ HOST1=wayne-000
fvwmtest.sh: line 15: HOST1=wayne-000: command not found
+ echo

+ (( NUMBER = 1 + 1 ))
+ for line in '$FIXHOSTS'
+ HOST2=wayne-002
fvwmtest.sh: line 15: HOST2=wayne-002: command not found
+ echo

+ (( NUMBER = 2 + 1 ))
+ for line in '$FIXHOSTS'
+ HOST3=wayne-003
fvwmtest.sh: line 15: HOST3=wayne-003: command not found
+ echo

+ (( NUMBER = 3 + 1 ))

#done

echo $HOST1
+ echo

echo $HOST2
+ echo

echo $HOST3
+ echo

echo $HOST4
+ echo

他们为什么不回声?为什么他们没有被分配?

1 个答案:

答案 0 :(得分:0)

动态变量在bash中可能非常烦人。 declare命令可以提供帮助:

$ num=13
$ val="hello world"
$ declare "host$num=$val"
$ echo $host13
hello world

所以你想要:

num=0
while read -r line; do
    ((num++))
    declare host$num="$line"
done < /tmp/fixHosts.txt
num_hosts=$num

echo $host1 $host2 $host3 ...

注意:

更简单的是使用数组:如果你有bash版本4

mapfile -t hosts < /tmp/fixHosts.txt
num_hosts=${#hosts[@]}
echo ${hosts[0]} ${hosts[1]} ${hosts[2]} ...