Question

如何仅在一种模式下调用所有选项？例如：隐藏（＆＃34;房子，建筑，衣服＆＃34;）或隐藏（＆＃34;房子＆＃34;，＆＃34;建筑＆＃34;，＆＃34;衣服＆＃34;）......有可能吗？

// == shows all markers of a particular category and ensures the checkbox is checked
function show(category) {
    for (var i=0; i<locations.length; i++) {
        if (locations[i][2] == category) {
            markers[i].setVisible(true);
        }
    }
}
// hides all markers of a particular category and ensures the checkbox is cleared
function hide(category) {
    for (var i=0; i<locations.length; i++) {
        if (locations[i][2] == category) {
            markers[i].setVisible(false);
        }
    }
}
// show or hide the categories initially
hide("house");
hide("building");
hide("clothes");

全部谢谢：）

Answer 1

您可以使用javascript对象：

toggleShowHide({"house":true,"building":false,"clothes":true});
function toggleShowHide(options) {
  for(key in options)
  {
    if (options.hasOwnProperty(key)) {
      for (var i=0; i<locations.length; i++) {
          if (locations[i][2] == key) {
             markers[i].setVisible(options[key]);
          }
        }
      }
  }

}

请参阅hasOwnProperty

的说明

Answer 2

使用参数对象

function show() {
    for(var j = 0; j<arguments.length; j++){
      for (var i=0; i<locations.length; i++) {
        if (locations[i][2] == arguments[j]) {
            markers[i].setVisible(true);
        }
      }
    }
}
// hides all markers of a particular category and ensures the checkbox is cleared
function hide() {
    for(var j = 0; j<arguments.length; j++){
      for (var i=0; i<locations.length; i++) {
        if (locations[i][2] == arguments[j]) {
            markers[i].setVisible(false);
        }
      }
}
// show or hide the categories initially
hide("house", "building", "clothes");

具有许多值的调用函数

2 个答案: