我正在尝试计算以下架构的每个问题的投票数。
[
{
"_id": "564b9e13583087872176dbd2",
"question": "fav NFL team",
"choices": [
{
"text": "St. Louis Rams",
"_id": "564b9e13583087872176dbd7",
"votes": [
{
"ip": "::ffff:192.168.15.130",
"_id": "564b9e30583087872176dbd8"
},
{
"ip": "::ffff:192.168.1.1",
"_id": "564bb355e4e1b7200da92668"
}
]
},
{
"text": "Oakland Raiders",
"_id": "564b9e13583087872176dbd6",
"votes": [
{
"ip": "::ffff:192.168.1.135",
"_id": "564bb273e4e1b7200da92667"
}
]
},
{
"text": "Denver Broncos",
"_id": "564b9e13583087872176dbd5",
"votes": []
},
{
"text": "Kansas City Chiefs",
"_id": "564b9e13583087872176dbd4",
"votes": [
{
"ip": "::ffff:192.168.1.100",
"_id": "564bab48e4e1b7200da92666"
}
]
},
{
"text": "Detroit Lions",
"_id": "564b9e13583087872176dbd3",
"votes": [
{
"ip": "::ffff:192.168.15.1",
"_id": "564b9f41583087872176dbd9"
}
]
}
]
}
]
我假设我将不得不使用聚合和总和。 我能够得到选择数组的计数,但我不确定如何更深入。
db.polls.aggregate([{$unwind: '$choices'}, {$group:{_id:'$_id', 'sum':{$sum:1}}}])
“赞成NFL球队”的投票数为5。
另外,这里引用的是我生成模式的猫鼬代码
var mongoose = require('mongoose');
var voteSchema = new mongoose.Schema({
ip: 'String'
});
var choiceSchema = new mongoose.Schema({
text: String,
votes: [voteSchema]
});
exports.PollSchema = new mongoose.Schema({
question: {
type: String,
required: true
},
choices: [choiceSchema]
});
答案 0 :(得分:0)
我想出了如何在芒果中做到这一点,我需要另一个放松。
db.polls.aggregate([
{$unwind: '$choices'},
{$unwind:'$choices.votes'},
{$group:{
_id:'$_id',
'sum':{
$sum:1
}
}}
])
这里是mongoose
Poll.aggregate([
{$unwind: '$choices'},
{$unwind: '$choices.votes'},
{$group:{
_id: '$_id',
'sum': {
$sum:1
}
}}
], function(err, result) {
if (err) {
console.log(err);
}
res.json(result);
});