Question

给定一个界面：

public interface A {};

继承接口：

public interface B extends A {}

public interface C extends A {}

如何以编程方式扫描以查找B和C？即怎么做：

Type[] types = findAllSubInterfacesOfA(); // Returns [B.class, C.class]

注意：我试图在这里找到接口，不是类或实例。

Answer 1

以下代码段应该这样做。

public class FindSubinterfaces {

    public static void main(String[] args) {
        Class clazz = A.class;

        Reflections reflections = new Reflections(new ConfigurationBuilder()
                .setUrls(Arrays.asList(ClasspathHelper.forClass(clazz))));

        Set<Class<? extends List>> subTypes = reflections.getSubTypesOf(clazz);
        for (Class c : subTypes) {
            if (c.isInterface()) {
                System.out.println("subType: " + c.getCanonicalName());
            }
        }
    }
}

interface A {
};

interface B extends A {
}

interface C extends A {
}

class CA implements A {
}

abstract class DC implements C {
}

输出

subInterface: sub.optimal.reflections.B
subInterface: sub.optimal.reflections.C

如何在Java中查找特定接口的所有（子）子接口？

1 个答案: