我有两个GPS坐标,例如:(44.40239182909422, 8.930511474608954)
和(30.297017883371236, 122.3822021484364)
我想知道这两点之间的距离。我不知道第一个坐标是否大于第二个坐标。
我正在尝试理解和修改此代码示例:
private double _distance(double lat1, double lon1, double lat2, double lon2) {
double theta = lon1 - lon2;
double dist = Math.sin(deg2rad(lat1)) * Math.sin(deg2rad(lat2)) + Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) * Math.cos(deg2rad(theta));
dist = Math.acos(dist);
dist = rad2deg(dist);
dist = dist * 60 * 1.1515; // 60 is the number of minutes in a degree; //1.1515 is the number of statute miles in a nautical mile.One nautical mile is the length of one minute of latitude at the equator.
dist = dist * 1.609344;
return (dist);
}
计算' theta'我添加了以下代码:
double theta = lon1 - lon2;
if(lon2>lon1)
theta = lon2 - lon1;
答案 0 :(得分:1)
距离函数将返回meteres中两点之间的距离
public double distance() {
double lat1 = 44.40239182909422;
double lon1 = 8.930511474608954;
double lat2 = 30.297017883371236;
double lon2 = 122.3822021484364;
double theta = lon1 - lon2;
double dist = Math.sin(deg2rad(lat1)) * Math.sin(deg2rad(lat2)) + Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) * Math.cos(deg2rad(theta));
dist = Math.acos(dist);
dist = rad2deg(dist);
dist = dist * 1.609344 * 1000;
return (dist); // 134910.69784909734
}
/* The function to convert decimal into radians */
private double deg2rad(double deg) {
return (deg * Math.PI / 180.0);
}
/* The function to convert radians into decimal */
private double rad2deg(double rad) {
return (rad * 180.0 / Math.PI);
}