我正在测试mysql和c#内容，我只使用控制台应用程序并将来将其改编为Windows窗体。发生了一个错误，我似乎无法修复它。
方法：
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using MySql.Data.MySqlClient;
namespace databaseTest
{
class Program
{
private MySqlConnection connection; //connection property
private string server;
private string database;
private string uid;
private string password;
static void Main(string[] args)
{
while (true)
{
Console.Clear();
Program myProg = new Program();
myProg.Initialize();
Console.WriteLine("Choose item;");
Console.WriteLine("<A> Add Record");
Console.WriteLine("<B> Delete Record");
Console.WriteLine("<C> Update Record");
Console.WriteLine("<D> Show Record");
Console.WriteLine("<E> Count Records");
Console.WriteLine("<F> Search Records");
Console.WriteLine("<X> Exit");
ConsoleKeyInfo myKey = Console.ReadKey();
if (myKey.Key == ConsoleKey.A)
{
myProg.Insert();
}
}
}
private void Initialize()
{
server = "localhost"; //local host (WAMP)
database = "my_db"; //database name
uid = "root"; //database username
password = ""; //database password
string connectionString;
connectionString = "SERVER=" + server + ";" + "DATABASE=" +
database + ";" + "UID=" + uid + ";" + "PASSWORD=" + password + ";";
connection = new MySqlConnection(connectionString);
}
private bool OpenConnection()
{
try
{
connection.Open();
return true;
}
catch (MySqlException ex)
{
//When handling errors, you can your application's response based
//on the error number.
//The two most common error numbers when connecting are as follows:
//0: Cannot connect to server.
//1045: Invalid user name and/or password.
switch (ex.Number)
{
case 0:
Console.WriteLine("Cannot connect to server. Contact administrator");
break;
case 1045:
Console.WriteLine("Invalid username/password, please try again");
break;
}
return false;
}
}
private bool CloseConnection()
{
try
{
connection.Close();
return true;
}
catch (MySqlException ex)
{
Console.WriteLine(ex.Message);
return false;
}
}
public void Insert()
{
List<databaseOperations.User> user = new List<databaseOperations.User>();
databaseOperations.User x = new databaseOperations.User();
Console.Clear();
Console.WriteLine("---> Insert Record\n");
Console.WriteLine("Enter numeric ID: (***)");
int ID = int.Parse(Console.ReadLine());
Console.WriteLine("Enter first name:");
String firstName = Console.ReadLine();
Console.WriteLine("Enter last name:");
String lastName = Console.ReadLine();
Console.WriteLine("Enter telephone:");
String telephone = Console.ReadLine();
x.ID = ID;
x.firstName = firstName;
x.lastName = lastName;
x.telephone = telephone;
user.Add(x);
databaseOperations.InsertToDatabase(x);
}
}
}
Dll方法：
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using MySql.Data.MySqlClient;
namespace databaseTest
{
class databaseOperations
{
private MySqlConnection connection; //connection property
private string server;
private string database;
private string uid;
private string password;
public class User
{
public int ID { get; set; }
public string firstName { get; set; }
public string lastName { get; set; }
public string telephone { get; set; }
}
private void Initialize()
{
server = "localhost"; //local host (WAMP)
database = "my_db"; //database name
uid = "root"; //database username
password = ""; //database password
string connectionString;
connectionString = "SERVER=" + server + ";" + "DATABASE=" +
database + ";" + "UID=" + uid + ";" + "PASSWORD=" + password + ";";
connection = new MySqlConnection(connectionString);
}
private bool OpenConnection()
{
try
{
connection.Open();
return true;
}
catch (MySqlException ex)
{
//When handling errors, you can your application's response based
//on the error number.
//The two most common error numbers when connecting are as follows:
//0: Cannot connect to server.
//1045: Invalid user name and/or password.
switch (ex.Number)
{
case 0:
Console.WriteLine("Cannot connect to server. Contact administrator");
break;
case 1045:
Console.WriteLine("Invalid username/password, please try again");
break;
}
return false;
}
}
private bool CloseConnection()
{
try
{
connection.Close();
return true;
}
catch (MySqlException ex)
{
Console.WriteLine(ex.Message);
return false;
}
}
public void InsertToDatabase(int ID, string firstName, string lastName, string telephone)
{
string query = "INSERT INTO tbl_user (ID,First_Name,Last_Name,Telephone) VALUES('" + ID + "', '" + firstName + "','" + lastName + "','" + telephone + "')";
if (this.OpenConnection() == true)
{
MySqlCommand cmd = new MySqlCommand(query, connection);
cmd.ExecuteNonQuery();
this.CloseConnection();
Console.WriteLine("\n -->Record Added - Press enter to continue...");
Console.ReadLine();
}
}
}
}
我正在尝试使用InsertToDatabase
我得到的错误是：
错误CS7036没有给出的参数对应于'databaseOperations.InsertToDatabase（int，string，string，string）所需的形式参数'firstName'
如果我改变
databaseOperations.InsertToDatabase(ID, firstName, lastName, telephone);
我得到了这个错误：
严重级代码说明项目文件行 错误CS0120非静态字段，方法或属性'databaseOperations.InsertToDatabase（int，string，string，string）需要对象引用
答案 0 :(得分：4)
您还没有创建links = soup.find_all('a href')
for link in links:
print(link)
的实例。方法databaseOperations是instance method。
另外，正如您所提到的，您是c＃的新手 - 您应该使用大写首字母（Pascal案例）命名类，并使用小写首字母（驼峰案例）命名：https://msdn.microsoft.com/en-us/library/x2dbyw72.aspx
我已经编写了以下示例，假设您已将databaseOperations.InsertToDatabase课程重命名为databaseOperations：
DatabaseOperations另请注意，您的DatabaseOperations databaseOperations = new DatabaseOperations();
databaseOperations.InsertToDatabase(x.ID, x.firstName, x.lastName, x.telephone);
课程目前尚未拨打DatabaseOperations。您可能需要从构造函数中调用它，例如：
Initialize