Question

正如我在标题中所提到的，我想使用phpmailer将联系表单发送到gmail。我已经为我的联系表单编写了代码，sendmail php文件如下所示。

我在$ mail-＆gt;行中的sendemail.php文件上出错了端口= 465;

contact.html

<script type="text/javascript" src="jquery-2.1.4.min.js"></script>
<script type="text/javascript">
$(function(){

$('input[type=submit]').click(function(){

$.ajax({
    url: "sendemail.php",
    type: 'POST',
    data: $("#myForm").serialize(),
    success: function(data){
       $('#result').html(data);
    }
});

});

});
</script>

    <form action="" method="post" onsubmit="return false;" id ="myForm">
          <input type="text" class="form-control" required="required" name="guest_name" placeholder="Name">
          <input type="text" class="form-control" required="required" name="guest_mail" placeholder="Email address">
          <input type="text" class="form-control" required="required" name="guest_cont" placeholder="Contact No.">
          <input type="text" class="form-control" required="required" name="guest_comp" placeholder="Company Name">
          <textarea name="guest_msg" id="message" required="required" class="form-control" rows="8" placeholder="Enquery or Feedback"></textarea>
          <input type="submit" name="submit" value="Submit" class="btn btn-danger btn-lg">
     </form>

和sendemail.php

<?php


    $subject = "Query/Feedback"; 
    $name = $_POST['guest_name']; 
    $email = $_POST['guest_mail']; 
    $contact = $_POST['guest_cont']; 
    $company = $_POST['guest_comp'];
    $message = $_POST['guest_msg']; 

    $email_from = $email;
    $email_to = 'rexxxxxxxxxxxxd@gmail.com';

    if($sender== '' || $mail_id== '' || $cont_no== '' || $company== '' || $msg_txt== ''){
        echo "check the fields";
    }else{

    $subject='Query from '.$sender;
    $message='Dear Sir,<br><br>'.$msg_txt.'<br><br>From: '.$sender.'<br>Contact: '.$cont_no.'<br>Company Name: '.$company;

    require "phpmailer/class.phpmailer.php";  //including the phpmailer file

    //Installing Class
    $mail = new PHPMailer();

    // Set up SMTP
    $mail->IsSMTP();
    $mail->SMTPAuth = true;
    $mail->SMTPSecure = "ssl";
    $mail->Host = "smtp.gmail.com;"
    $mail->Port = 465;
    $mail->Encoding = '7bit';

    // Authentication
    $mail->Username = "mymailid@gmail.com"
    $mail->Password = "mypassword"

    // Compose
    $mail->SetFrom($_POST['guest_mail'], $_POST['guest_name']);
    $mail->AddReplyTo($_POST['guest_mail'], $_POST['guest_name']);
    $mail->Subject = "/new Contact From Enquery"
    $mail->MsgHTML($guest_msg);

    // Send To
    $mail->AddAddress($email_to, "Banti");
    $result = $mail->Send();
    if($result)
        {
        echo "Thank you for your Feedback";
    }

    }


?>

Answer 1

由于我的低代表我还不能发表评论，所以也许我误解了这个问题..但是，如果“我设置了错误设置端口”你的意思是你的PHP脚本运行但电子邮件没有被发送，问题可能是gmail需要：

$mail->SMTPSecure = "tls";
$mail->Host = "smtp.gmail.com";
$mail->Port = 587;

我也将PHPMailer与gmail一起使用。

修改

你错过了一些“;” ：

$mail->Host = "smtp.gmail.com;" // you have this $mail->Host = "smtp.gmail.com"; // you need this $mail->Username = "mymailid@gmail.com"; // add this $mail->Password = "mypassword"; // add this

使用phpmailer通过联系表单发送邮件

1 个答案: