我是Android开发的新手。 我在使用web api消费复杂类型时遇到了问题。
情景::
我使用visual studio创建了一个web api方法，用于检查我的sql 2012数据库中的用户凭据。
API方法::
[HttpPost]
public Login PostLogin(JObject jsonData)
{
dynamic json = jsonData;
string Jusername = json.username.Value;
string JPassword = json.Password.Value;
int JIsEncrypted = Convert.ToInt32(json.IsEncrypted.Value);
Login m = db.sp_GetValidUserLoginDetails(Jusername, JPassword,JIsEncrypted)
.Select(x => new Login()
{
Employee_Id = x.Employee_Id,
Employee_Code = x.Employee_Code,
Employee_FirstName = x.Employee_FirstName,
Employee_LastName = x.Employee_LastName,
Employee_EmailId = x.Employee_EmailId,
Employee_ContactNumber = x.Employee_ContactNumber,
IsActive = Convert.ToBoolean(x.IsActive),
Created_Date = x.Created_Date,
Modified_Date = x.Modified_Date,
User_Name = x.User_Name,
User_Password = x.User_Password,
error = x.error
}).ToList().FirstOrDefault();
return m;
}
}
在Android项目中，我尝试了以下两种方法
方法1 ::
public String requestWebService(String serviceUrl, login logg) throws UnsupportedEncodingException {
InputStream inputStream = null;
JSONObject log = new JSONObject();
String result = "";
try {
log.put("username", logg.username);
log.put("Password", logg.password);
log.put("IsEncrypted", 0);
} catch (JSONException e) {
e.printStackTrace();
}
HttpClient httpclient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(serviceUrl);
String json = "";
json = log.toString();
httpPost.setEntity(new StringEntity(log.toString(), "UTF-8"));
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
try {
HttpResponse httpResponse = httpclient.execute(httpPost);
if(inputStream != null)
result = convertInputStreamToString(inputStream);
} catch (IOException e) {
e.printStackTrace();
}
Toast.makeText(this, "done", Toast.LENGTH_LONG).show();
return result;
}
public String Requesting(String url, login log) throws IOException, JSONException {
URL object=new URL(url);
HttpURLConnection con = (HttpURLConnection) object.openConnection();
con.setDoOutput(true);
con.setDoInput(true);
con.setRequestProperty("Content-Type", "application/json");
con.setRequestProperty("Accept", "application/json");
con.setRequestMethod("POST");
OutputStreamWriter wr = new OutputStreamWriter(con.getOutputStream());
wr.write(log.toString());
wr.flush();
StringBuilder sb = new StringBuilder();
int HttpResult = con.getResponseCode();
BufferedReader br = new BufferedReader(new InputStreamReader(con.getInputStream(),"utf-8"));
String line = null;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
System.out.println(""+sb.toString());
return null;
}
问题::
如何将我的用户名和密码作为复杂的类型集合从Android应用程序传递到此webapi并在android项目中获取响应？ 我每次都得到null JsonObject。
请帮助。谢谢提前
我已经检查了以下链接但是这里但这不适用于我的情况。 Android App with ASP.NET WebAPi Server - send complex types
答案 0 :(得分：0)
因为我想要将 JSon String 发送到Web服务（webapi）。我对吗 ？如果是，那么您可以使用几行代码完成此操作。在这里，您将使用HttpUrlConnection类在webapi和Android App之间建立连接。
我在这里发布了一个示例代码，您可以使用它以JSONObject的形式将json字符串发送到webapi。
private class BackgroundOperation extends AsyncTask<String, Void, String> {
JSONObject josnobj ;
BackgroundOperation(JSONObject josnobj){
this.josnobj = josnobj
}
@Override
protected String doInBackground(String... params)
//Your network connection code should be here .
String response = postCall("Put your WebService url here");
return response ;
}
@Override
protected void onPostExecute(String result) {
//Print your response here .
Log.d("Post Response",result);
}
@Override
protected void onPreExecute() {}
@Override
protected void onProgressUpdate(Void... values) {}
}
public static String postCall(String uri) {
String result ="";
try {
//Connect
HttpURLConnection urlConnection = (HttpURLConnection) ((new URL(uri).openConnection()));
urlConnection.setDoOutput(true);
urlConnection.setRequestProperty("Content-Type", "application/json");
urlConnection.setRequestProperty("Accept", "application/json");
urlConnection.setRequestMethod("POST");
urlConnection.connect();
//Write
OutputStream outputStream = urlConnection.getOutputStream();
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(outputStream, "UTF-8"));
//Call parserUsuarioJson() inside write(),Make sure it is returning proper json string .
writer.write(josnobj.toString());
writer.close();
outputStream.close();
//Read
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream(), "UTF-8"));
String line = null;
StringBuilder sb = new StringBuilder();
while ((line = bufferedReader.readLine()) != null) {
sb.append(line);
}
bufferedReader.close();
result = sb.toString();
} catch (UnsupportedEncodingException e){
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return result;
}
现在，您可以使用以下代码从您的活动的onCreate（）函数中调用以上内容。
JSONObject jobj = new JSONObject();
jobj.put("name","yourname");
jobj.put("email","mail");
jobj.put("pass","pass");
new BackgroundOperation(jobj).execute();
注意：不要忘记在manifest.xml中提及以下权限
<uses-permission android:name="android.permission.INTERNET" />
答案 1 :(得分：0)
最后，我得到了解决方案。希望这有助于某人。
我们需要通过添加FromBody来改变HttpPost方法的签名
[HttpPost]
public Login PostLogin([FromBody] string jsonData)
{
dynamic json = jsonData;
string Jusername = json.username.Value;
string JPassword = json.Password.Value;
int JIsEncrypted = Convert.ToInt32(json.IsEncrypted.Value);
Login m = db.sp_GetValidUserLoginDetails(Jusername,JPassword,JIsEncrypted)
.Select(x => new Login()
{
Employee_Id = x.Employee_Id,
Employee_Code = x.Employee_Code,
Employee_FirstName = x.Employee_FirstName,
Employee_LastName = x.Employee_LastName,
Employee_EmailId = x.Employee_EmailId,
Employee_ContactNumber = x.Employee_ContactNumber,
IsActive = Convert.ToBoolean(x.IsActive),
Created_Date = x.Created_Date,
Modified_Date = x.Modified_Date,
User_Name = x.User_Name,
User_Password = x.User_Password,
error = x.error
}).ToList().FirstOrDefault();
return m;
}
}
还需要在webapi.config文件中添加以下行，以便将默认格式化程序设置为JSON
config.Formatters.RemoveAt(0);
config.Formatters.Add(new JsonMediaTypeFormatter());
config.Formatters.JsonFormatter.MediaTypeMappings.Add(
new QueryStringMapping("frmt", "json",
new MediaTypeHeaderValue("application/json")));