Question

我想在Linux C中获取星期六的星期几。使用函数时间和本地时间，我得到了今天的日期和时间详细信息。如何进一步了解星期六的约会？

#include <time.h> 
#include <stdio.h> 
#include <string.h> 
int main() 
{ 
char date[20]; 
struct tm *curr_tm = NULL; 
time_t curr_time; 
curr_time = time(NULL); 
curr_tm = localtime(&curr_time); 
curr_tm->tm_wday = 6; 
//Refers to saturday. 
printf("new date %d\t%d\t%d\n", curr_tm->tm_mday, curr_tm->tm_mon, curr_tm->tm_year+1900); 
return 1; 
}

我该如何处理？

Answer 1

struct tm orig;
// ...
// struct tm correctly set with everything within range.
orig.tm_mday += 6 - orig.tm_wday;
mktime(&orig);

tm_mday是自星期日以来的天数。因此，6减去这是直到星期六的天数（如果今天是星期六它什么都不做）。这会使结构超出范围，mktime已修复。

编辑：

curr_time->tm_mday += 6 - curr_time->tm_wday;
mktime(curr_time);

Answer 2

根据您的代码，以下内容将为您提供下周六（今天是星期六）。

#include <time.h>
#include <stdio.h>
#include <string.h>
int main() {
    char date[20];
    struct tm *curr_tm = NULL;
    time_t curr_time;
    curr_time = time(NULL);
    curr_tm = localtime(&curr_time);

    // Add the difference between todays day of week and Saturday, then re-make.
    curr_tm->tm_mday += 6 - curr_tm->tm_wday;
    mktime (curr_tm);

    printf("new date %d\t%d\t%d\n",
        curr_tm->tm_mday, curr_tm->tm_mon+1, curr_tm->tm_year+1900);
    return 1;
}

您可以将curr_tm->tm_mday += 6 - curr_tm->tm_wday;行替换为：

curr_tm->tm_mday += (curr_tm->tm_wday == 6) ? 7 : 6 - curr_tm->tm_wday;

即使今天是星期六，也要到下个星期六。

需要在Linux C中获得星期六的星期几

2 个答案: