Question

我试图编写一个程序，在数组[]数组中生成并存储20个随机数，并要求用户输入他们的猜测。如果它们的数字出现在数组中，则每次出现时得到10个点，打印数组并找到幸运数字的所有位置。如果它没有出现在数组中，我必须打印数组的最低和最高值，并且只允许再尝试一次。如果玩家第二次获得正确，则每次出场获得1分。例如：Data[]={3,1,8,31,25,6,3,20,41,12,3,23,7,3,65,49,5,0,13,17} 如果用户输入3，则程序将输出

3 can be found on the following positions:
0 6 10 13
3 appears 4 times. You get 40 points!

并且如果用户输入Data[]={3,1,8,31,25,6,3,20,41,12,3,23,7,3,65,49,5,0,13,17}，则为2，然后程序将输出

Sorry your lucky number 2 is not in the array! 
Hint: Lowest Value:1 Highest Value 65  Try again with a different number in this range.

如果他们在第二次尝试时输入65，则程序将输出

You get 1 point(s)!

这是我尝试的代码，但它无效。它一直告诉我我的数字不在数组中。最低和最高值有效。我不知道如何解决它。我必须在明天完成这件事。任何帮助将不胜感激。

String input1 = JOptionPane.showInputDialog("Please enter your lucky number between 0 and 100.");
luck=Integer.parseInt(input1);
System.out.println("Input " +luck);

int Data[] = new int [20];
for( int i=0; i<Data.length;++i){
    Data[i] = (int) (Math.random() * 100);
    System.out.print(Data[i]+ " \t");
}
for( int i=0; i<Data.length;++i){
    if(Data[i]==luck){
        System.out.println(luck+ " can be found in the following positions: ");
        System.out.println(i);
        score=score+10;
        System.out.println(luck+ " appears " +(luck/10)+ " times. You get " +score+ " points.");
    }else if(Data[i]!=luck){
        Arrays.sort(Data);
        System.out.println();
        System.out.println(luck+ " is not in the array.");
        System.out.println("Hint: " +Data[0]+ " is the lowest value and " +Data[19]+ " is the highest.");
        input1 = JOptionPane.showInputDialog("Please enter another number between 0 and 100.");
        luck=Integer.parseInt(input1);
    }
}
System.out.println();
System.out.println("Score: " +score);

}}

Answer 1

问题是您没有针对数组中的每个值检查您的值。如果输入的值与数组中的第一个值（i = 0）不匹配，那么您要求用户提供另一个值。

您需要做的是询问一个值，将其与表中的每个值进行比较，然后做出决定。无论是现在还是不存在。

我添加了一个布尔值。如果我们找到我们的号码，我们将其设置为true，否则我们会显示该消息并要求用户重试。

试试这个：

    boolean found = false;
    for( int i=0; i<Data.length;++i){
        if(Data[i]==luck){
            System.out.println(luck+ " can be found in the following positions: ");
            System.out.println(i);
            score=score+10;
            System.out.println(luck+ " appears " +(luck/10)+ " times. You get " +score+ " points.");
            found = true;
        }
    }
    if(!found){
            Arrays.sort(Data);
            System.out.println();
            System.out.println(luck+ " is not in the array.");
            System.out.println("Hint: " +Data[0]+ " is the lowest value and " +Data[19]+ " is the highest.");
            input1 = JOptionPane.showInputDialog("Please enter another number between 0 and 100.");
            luck=Integer.parseInt(input1);
        }

最后，您需要在循环中实现一个计数器，然后根据需要显示您的信息......现在，它将显示＆＃34;＃可以在以下位置找到＃34;以及在数组中找到的每个实例的其他消息。实现一个计数器，以及一种跟踪找到的值索引的方法，然后你可以从for循环外部连贯地显示所有这些信息

编辑：为您提供更完整的实施...... 这段代码基本上可以带你到你需要去的地方：

public static void main(String[] args) {
    int Data[] = new int [20];
    for( int i=0; i<Data.length;++i){
        Data[i] = (int) (Math.random() * 100);
        System.out.print(Data[i]+ " \t");
    }

    while(true){
        String input1 = JOptionPane.showInputDialog("Please enter your lucky number between 0 and 100.");
        int luck=Integer.parseInt(input1);
        int score = 0;
        String positions = "";
        int counter = 0;
        System.out.println("Input " +luck);

        boolean found = false;
        for( int i=0; i<Data.length;++i){
            if(Data[i]==luck){
                positions +=  i + " ";
                counter++;
                score=score+10;
                found = true;
            }
        }
        if(found){
            System.out.println(luck+ " can be found in the following positions: ");
            System.out.println(positions);
            System.out.println(luck+ " appears " + counter + " times. You get " +score+ " points.");

        }
        else{
            Arrays.sort(Data);
            System.out.println();
            System.out.println(luck+ " is not in the array.");
            System.out.println("Hint: " +Data[0]+ " is the lowest value and " +Data[19]+ " is the highest.");
        }

        System.out.println();
        System.out.println("Score: " +score);
    }

}

在数组中查找数字的位置并给出点，Java

1 个答案: