从Android Studio中的未发布到应用的图库中选择图像?

时间:2015-11-11 05:15:32

标签: android

我真的很新,并且正在浏览Android Studio上的一些教程,以获得一些帮助来创建一个简单的图像视图,只需从图库中选择一个图像并将其显示在页面上。我可以点击并拉出画廊但是从画廊中选择图像后它不会显示。我查看了几个教程,但是我没有看到任何遗漏的东西?有什么帮助吗?

android manifest

    <?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="adamnate.ddproject" >

    <application
        android:allowBackup="true"
        android:icon="@mipmap/ic_launcher"
        android:label="@string/app_name"
        android:supportsRtl="true"
        android:theme="@style/AppTheme" >
        <activity android:name=".MainActivity" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>
    </application>
<uses-permission android:name="android.permission.INTERNET"/>
    <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/>
    <uses-permission a

ndroid:名称= “android.permission.WRITE_EXTERNAL_STORAGE”/&GT;

MainActivity.xml

 package adamnate.ddproject;

 import android.content.Intent;
 import android.net.Uri;
 import android.provider.MediaStore;
 import android.support.v7.app.AppCompatActivity;
 import android.os.Bundle;
 import android.view.View;
 import android.widget.Button;
 import android.widget.ImageView;


public class MainActivity extends AppCompatActivity {
private static final int RESULT_LOAD_IMAGE = 1;
ImageView imageToUpload;
Button bUploadImage;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

     imageToUpload = (ImageView) findViewById(R.id.imageToUpload);
     bUploadImage = (Button) findViewById(R.id.bUploadImage);

    imageToUpload.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            Intent intent = new Intent();
            intent.setType("image/*");
            intent.setAction(Intent.ACTION_GET_CONTENT);
            startActivityForResult(Intent.createChooser(intent, "Select Picture"), 1);
        }
    });
}





@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (resultCode == RESULT_OK) {
        if (requestCode ==11)
       imageToUpload.setImageURI(data.getData());
    }
 }
}

activity_main

<?xml version="1.0" encoding="utf-8"?>
<ScrollView xmlns:android="http://schemas.android.com/apk/res/android"
   android:layout_width="match_parent"
    android:padding="10dp"
    android:layout_height="match_parent">

<LinearLayout
    android:orientation="vertical"
    android:layout_width="match_parent"
    android:layout_height="match_parent">

    <ImageView
        android:layout_width="150dp"
        android:layout_height="150dp"
        android:id="@+id/imageToUpload"
        android:layout_gravity="center_horizontal" />

    <Button
        android:id="@+id/bUploadImage"
        android:text="Upload Image"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        />
</LinearLayout>
</ScrollView>

1 个答案:

答案 0 :(得分:0)

使用此

requestCode == 1

而不是

requestCode == 11

因为你在调用startActivityForResult()

时在requestCode参数上放了1