Question

请告诉我，如何转换以下数据，

[id]  cost1  cost2    year 
   1      5     10    2010 
   1      4     15    2011 
   2     10     10    2010

采用此格式['年'到列标题的行'

id [cost1-2010] [cost2-2010] [cost1-2011] [cost2-2011] 
 1           5           10            4           15 
 2          10           10            0            0

Answer 1

使用PIVOT

示例：http://www.simple-talk.com/community/blogs/andras/archive/2007/09/14/37265.aspx

Answer 2

尝试这样的事情：

DECLARE @YourTable table (id int, cost1 int, cost2 int, year int)
INSERT @YourTable VALUES (1,5,10,2010)
INSERT @YourTable VALUES (1,4,15,2011)
INSERT @YourTable VALUES (2,10,10,2010)

SELECT
    id
        ,SUM(CASE WHEN year=2010 THEN cost1 else 0 END) AS "Cost1-2010"
        ,SUM(CASE WHEN year=2010 THEN cost2 else 0 END) AS "Cost2-2010"
        ,SUM(CASE WHEN year=2011 THEN cost1 else 0 END) AS "Cost1-2011"
        ,SUM(CASE WHEN year=2011 THEN cost2 else 0 END) AS "Cost2-2010"
    FROM @YourTable
    GROUP BY id

输出

id          Cost1-2010  Cost2-2010  Cost1-2011  Cost2-2010
----------- ----------- ----------- ----------- -----------
1           5           10          4           15
2           10          10          0           0

(2 row(s) affected)

Answer 3

如果你想根据数据动态地做这件事，那么比仅仅使用PIVOT更困难。对于PIVOT或条件求和技术

[2010Values] = ( SUM(Case when year = 2010 then FieldValue Else 0 End)

您必须提前知道列名。

如果您希望根据收到的数据动态设置列名，那么您将不得不采用可能变得丑陋的动态SQL路由。

Answer 4

查看有关this post的讨论。那应该是你拨打的。

SQl Server 2005：列到列 - 如何应对这一挑战？

4 个答案: