Question

JUST试图将电子邮件地址链接到简单表单，但错误仍在继续，我还无法修复。能帮我理解这个错误究竟意味着什么吗？以及摆脱它的可能方法。

Environment:

Request Method: POST
Request URL: http://127.0.0.1:8000/contact/

Django Version: 1.8.5
Python Version: 3.5.0
Installed Applications:
('django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'newsletter')
Installed Middleware:
('django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.auth.middleware.SessionAuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware',
'django.middleware.security.SecurityMiddleware')


Traceback:
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35-32\lib\site-        packages\django\core\handlers\base.py" in get_response
132.                     response = wrapped_callback(request,   *callback_args,      **callback_kwargs)
File "c:\Windows\SysWOW64\src\newsletter\views.py" in contact
66.                 fail_silently=True)
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35-32\lib\site-  packages\django\core\mail\__init__.py" in send_mail
62.     return mail.send()
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35-32\lib\site-packages\django\core\mail\message.py" in send
303.         return self.get_connection(fail_silently).send_messages([self])
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35-32\lib\site-packages\django\core\mail\backends\smtp.py" in send_messages
100.             new_conn_created = self.open()
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35-32\lib\site-packages\django\core\mail\backends\smtp.py" in open
58.             self.connection = connection_class(self.host, self.port, **connection_params)
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35- 32\lib\smtplib.py" in __init__
251.             (code, msg) = self.connect(host, port)
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35-32\lib\smtplib.py" in connect
335.         self.sock = self._get_socket(host, port, self.timeout)
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35-32\lib\smtplib.py" in _get_socket
306.                                         self.source_address)
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35-32\lib\socket.py" in create_connection
689.     for res in getaddrinfo(host, port, 0, SOCK_STREAM):
File "C:\Users\Lokesh\AppData\Local\Programs\Python\Python35- 32\lib\socket.py" in getaddrinfo
728.     for res in _socket.getaddrinfo(host, port, family, type, proto, flags):

Exception Type: gaierror at /contact/
Exception Value: [Errno 11001] getaddrinfo failed

Errno 11001] getaddrinfo失败了

0 个答案: